7/(3 - x)
Let the number be 'x'. Quotient of 80 and x would be : 80/x
4 + (x/3) >= x
The algebraic expression for "twice a number" would be 2x, where x represents the unknown number. To find the quotient of 2x and 6, you would divide 2x by 6, which simplifies to (2x) / 6. This can be further simplified to x / 3, which represents the final quotient of twice a number and 6 in algebraic expression.
X/5= 136; X= 136x5 = 668; 668+3=671
3 divided by x
3 divided by x
let X = number quotient = x/4 x/4 + 9 = 12 x/4 = 3 x = 12
8/3(x)=
7/(3 - x)
Let the number be 'x'. Quotient of 80 and x would be : 80/x
4 + (x/3) >= x
x/3 - 9 = 18 x = 81
x/(10-5) = 3 x/5 = 3 x = 3*5 = 15
x/(10-5) = 3 x/5 = 3 x = 3*5 = 15
X/5= 136; X= 136x5 = 668; 668+3=671
If the number is x then: x+4-9 = -2 and so x = 3