The slope of the perpendicular to the line passing through P1(3,6) and P2(5,1) is 2/5.
Note: the slope of the original line is (change in y)/(change in x), yielding -5/2. The slope of the perpendicular is the negative reciprocal, 2/5
The slope is -9.
If you mean points of (-2, -1) and (3, 5) then the slope is 6/5
If you mean points of (055, 18) and (566, 81) then the slope works out as 9/73
84
It is: (5-4)/(2-0) = 1/2
Points: (5, -1) and (2, -5) Slope: 4/3 Perpendicular slope: -3/4
Infinite. The line is perpendicular to the ordinate.
To find the perpendicular distance between two points, you can use the distance formula and the concept of perpendicular lines. First, calculate the distance between the two points using the distance formula. Then, find the slope of the line passing through the two points. The perpendicular distance is the length of the line segment that connects the two points and forms a right angle with the line passing through them.
Points: (3,-4) and (-1, -2) Midpoint: (1,-3) Slope: -1/2 Perpendicular slope: 2 Perpendicular bisector equation in slope intercept form: y = 2x-5
Another set of points are needed to find the slope.
The slope is -9.
The slope is -9.
17
That depends on the points in order to find the slope whereas no points have been given.
Points: (3, 4) and (2, 1) Slope: 3
If you mean points of (-2, -1) and (3, 5) then the slope is 6/5
thanks you for your help