The slope of the perpendicular to the line passing through P1(3,6) and P2(5,1) is 2/5.
Note: the slope of the original line is (change in y)/(change in x), yielding -5/2. The slope of the perpendicular is the negative reciprocal, 2/5
The slope is -9.
If you mean points of (-2, -1) and (3, 5) then the slope is 6/5
If you mean points of (055, 18) and (566, 81) then the slope works out as 9/73
84
It is: (5-4)/(2-0) = 1/2
Points: (5, -1) and (2, -5) Slope: 4/3 Perpendicular slope: -3/4
Infinite. The line is perpendicular to the ordinate.
Points: (3,-4) and (-1, -2) Midpoint: (1,-3) Slope: -1/2 Perpendicular slope: 2 Perpendicular bisector equation in slope intercept form: y = 2x-5
Another set of points are needed to find the slope.
The slope is -9.
The slope is -9.
17
That depends on the points in order to find the slope whereas no points have been given.
Points: (3, 4) and (2, 1) Slope: 3
If you mean points of (-2, -1) and (3, 5) then the slope is 6/5
thanks you for your help
If the line passing through these points is a straight line then it has a positive gradient.