Q: The sum of 19 and the cube of x?

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19 x 19 x 19 = 6859

Twice divided by the cube of the sum of x and 2 is equal to 2 times the reciprocal of ((x + 2) cubed)).

it will be a cube or a to the power of 3.

x2 + x = 380 x2 + x - 380 = 0 (x + 20)(x - 19) x = 19, -20

19

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19+x^3 is already in simplest terms

the cube of the sum x and 4

19 x 19 x 19 = 6859

Twice divided by the cube of the sum of x and 2 is equal to 2 times the reciprocal of ((x + 2) cubed)).

x to the power (19/3).

it will be a cube or a to the power of 3.

No. 133 = 7 x 19

(7 x 7 x 7) - 19 = 324

It is (x + y)^3 - sqrt(5x + 3y) and there is no sensible simplification of this expression.

x2 + x = 380 x2 + x - 380 = 0 (x + 20)(x - 19) x = 19, -20

8 is the same as the sum of the digits of its cube, 512.

x is your number, so 2x + 17 =55. Solving for x = 19