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∙ 10y agoIt is (x + y)^3 - sqrt(5x + 3y) and there is no sensible simplification of this expression.
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∙ 8y agothe square root of the sum of the squares of three perpendicular edges.
The numbers are: 6 plus square root of 27 and 6 minus square root of 27
(4 factorial divided by .4) minus (the square root of 4 divided by .4) or 44 divided by (the square root of 4 divided by .4)
You can. Just add the numbers together, and find their square root. One plus three is four; the square root of the sum is two.
No. The right hand side is always greater - unless both components are zero.
27
the square root of the sum of the squares of three perpendicular edges.
The numbers are: 6 plus square root of 27 and 6 minus square root of 27
It's not. Take 49 and 16 for example. The square root of the sum is the square root of 65. The sum of the square roots is 11.
27 27 = 3*3*3 (3 cubed = 27) 2+7 = 9 The square root of 9 is 3.
27. Here you just have to plug stuff in until it works. That's my philosophy.
(4 factorial divided by .4) minus (the square root of 4 divided by .4) or 44 divided by (the square root of 4 divided by .4)
Well, let's see. Perfect cubes that are two digits: 27 64 Could it be 27? Well, 2+7 is 9, and that's a perfect square with a square root of 3, and the cube root of 27 is three. Looks like we've found our answer, especially since 6+4 = 10, which is NOT a perfect square.
false
You can. Just add the numbers together, and find their square root. One plus three is four; the square root of the sum is two.
If you have a data set, simply take the square root of the sum of the squares of the data points. Let's say you have three numbers a, b, and c. RSS = SQRT(a2 + b2 + c2).
The square root of 100 = 10 The square root of 225 = 15 The sum = 10 + 15 = 25