0
Add your answer:
Earn +20 pts
What is four times the sum of a number and 3?
4(N-3) is the formula, do the math from there and you get "N-3"
What is the equation for 3 times the sum of a number n and 7 equals 16?
3 (n + 7) = 16
How should seven times the sum of a number n and 3 be written as an algebraic expression?
7(n+3)
3 times the sum of a number and 5?
3*(n + 5) or 3n + 15
What is the product of 6 and the sum of 3 times a number n and 5?
6(3n+5)
How would you write out the sum of twice n and 3 times m?
sum = 2n + 3m
What is four times the sum of a number and 3?
4(N-3) is the formula, do the math from there and you get "N-3"
The sum of 6 times a number n and 4 times a number n is -30 what is the number?
10n = -30 n = -3
M times N equals 6300 if m and n are 2 digit multiples of 10 what could m and n be?
m and n are 70 and 90
What is the algebraic expression for the sum of 12 and 3 times a number?
Where n = any number, n(12+3)
What is the equation for 3 times the sum of a number n and 7 equals 16?
3 (n + 7) = 16
How should seven times the sum of a number n and 3 be written as an algebraic expression?
7(n+3)
What is the average of all the integer's of 13 to 37?
To find the (mean) average, add all the numbers and divide by the number of numbers. The sum of a series of digits (in arithmetic progression, like 13, 14, 15, ... 37) is sum = (first + last) x number_of_digits / 2 So their average is: average = ((first + last) x number_of_digits / 2) / number_of_digits = (first + last) / 2 = average of first and last digits! So the average of the numbers 13, 14, 15, ..., 37 is: average = (13 + 37) / 2 = 50 / 2 = 25 To find the sum of n digits starting with m: Sum = m + (m+1) + ... + (m+n-2) + (m+n-1) Rewrite the sum in reverse order: Sum2 = Sum = (m+n-1) + (m+n-2) + ... + (m+1) + m Add the two sums, term by term: Sum + Sum2 = 2 Sum = (m + (m+n-1)) + (m + (m+n-1)) + ... + (m + (m+n-1)) + (m + (m+n-1)) There are n terms, all (m + (m+n-1)), so: 2 Sum = (m + m+n-1) x n Sum = (m + m+n-1) x n / 2 But n is the number of digits, m is the first number and (m+n-1) is the last, so: Sum = (first + last) x number_of_digits / 2
3 times the sum of a number and 5?
3*(n + 5) or 3n + 15
What is the expresstion of 4 times the difference of a number an 1 is equal to 6 times the sum of a number times 3?
4*(n + 1) = 6*n*3
Write a program to find sum of all number between 100and 500?
long n= 100, m= 500;printf ("The sum is %ld\n", (m-n+1)*(m+n)/2);
How do you Work out average speeds for drag cars?
You record the various speed on the same distance and sum it. Then divide that sum with how many times you record it. Like for x meters : 1. a m/s 2. b m/s 3. c m/s . . n. y m/s The average would be : (a+b+c +...y)/n
Subjects
Math Science History Arts & Humanities Social Studies Engineering & Technology Business OtherTop Categories
Algebra Chemistry Biology World History English Language Arts Psychology Computer Science EconomicsProduct
Community Guidelines Honor Code Mobile App Answers+ Flashcard Maker Study Guides Math Solver FAQGet the Answers App
