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The simplest rule that will generate the 4 terms, and the nth term is

Un = 2n2 + n + 3

Then Sn = Sum for k = 1 to n of (2k2 + k + 3)

= 2*sum(k2) + sum(k) + sum(3)

= 2*n*(n+1)*(2n+1)/6 + n*(n+1)/2 + 3*n

= (2n3 + 3n2 + n)/3 + (n2 + n)/2 + 3n

= (4n3 + 9n2 + 23n)/6

The simplest rule that will generate the 4 terms, and the nth term is

Un = 2n2 + n + 3

Then Sn = Sum for k = 1 to n of (2k2 + k + 3)

= 2*sum(k2) + sum(k) + sum(3)

= 2*n*(n+1)*(2n+1)/6 + n*(n+1)/2 + 3*n

= (2n3 + 3n2 + n)/3 + (n2 + n)/2 + 3n

= (4n3 + 9n2 + 23n)/6

The simplest rule that will generate the 4 terms, and the nth term is

Un = 2n2 + n + 3

Then Sn = Sum for k = 1 to n of (2k2 + k + 3)

= 2*sum(k2) + sum(k) + sum(3)

= 2*n*(n+1)*(2n+1)/6 + n*(n+1)/2 + 3*n

= (2n3 + 3n2 + n)/3 + (n2 + n)/2 + 3n

= (4n3 + 9n2 + 23n)/6

The simplest rule that will generate the 4 terms, and the nth term is

Un = 2n2 + n + 3

Then Sn = Sum for k = 1 to n of (2k2 + k + 3)

= 2*sum(k2) + sum(k) + sum(3)

= 2*n*(n+1)*(2n+1)/6 + n*(n+1)/2 + 3*n

= (2n3 + 3n2 + n)/3 + (n2 + n)/2 + 3n

= (4n3 + 9n2 + 23n)/6

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