Let the first integer be x. Since the integers are consecutive odds we know that the integers are x, x+2, x+4,and x+6. Since the sum of all of these is 200 we can set up the equation:4x+12 = 200. Solving we get x=47. Therefore the integers are 47, 49, 51, and 53.
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There is no set of two consecutive integers equating to 200.
199 and 201.
All integers from 1 to 200.
There are 22 such numbers.
20,100