The sum of four consecutive odd integers is 200 find these integers?

Answer 1

Let the first integer be x. Since the integers are consecutive odds we know that the integers are x, x+2, x+4,and x+6. Since the sum of all of these is 200 we can set up the equation:4x+12 = 200. Solving we get x=47. Therefore the integers are 47, 49, 51, and 53.