There is no set of two consecutive integers equating to 200.
Let the first integer be x. Since the integers are consecutive odds we know that the integers are x, x+2, x+4,and x+6. Since the sum of all of these is 200 we can set up the equation:4x+12 = 200. Solving we get x=47. Therefore the integers are 47, 49, 51, and 53.
All integers from 1 to 200.
There are 22 such numbers.
20,100
"Consecutive" integers are integers that have no other integer between them.
There is no set of two consecutive integers equating to 200.
Let the first integer be x. Since the integers are consecutive odds we know that the integers are x, x+2, x+4,and x+6. Since the sum of all of these is 200 we can set up the equation:4x+12 = 200. Solving we get x=47. Therefore the integers are 47, 49, 51, and 53.
There are 9 integers.
The integers are 47, 49, 51, and 53. 47 * 53 = 2491
The smallest six consecutive composite integers are:90, 91, 92, 93, 94, 95.(And 96 is also composite, for a run of seven consecutive.)Is that what you were asking ?
Between 150 and 200.
114 115 116 117 118 119 120 121 122 123 124 125 126
196 is the square of 14...
101 and 103
8729
The sum of the first 200 positive integers is 19,900.