It has (7380+360)/180 = 43 sides
If the polygon has n sides then (n-2)*180 = 7380 So (n-2) = 7380/180 = 41 and then n = 43
four4 sides and 4 interior angles
sum interior angles = (number of sides - 2) × 180° → number of sides = sum interior angles ÷ 180° + 2 = 5040° ÷ 180° + 2 = 30
Four sides
There are 37 sides
If the sum of its interior angles add up to 7380 degrees then it will have 43 sides
43
If the polygon has n sides then (n-2)*180 = 7380 So (n-2) = 7380/180 = 41 and then n = 43
the sum of angles of a polygon is 180 x (n-2) whefe n is the number of sides re equating your question 7020 = 180 x (n - 2) = 180n -360 rearranging this gives 7380 = 180n therefore n is 7380 divided by 180 = 41 therefore a 41 sided polygon !!
four4 sides and 4 interior angles
4 sides and 4 interior angles
(number of sides -2)*180 = sum of interior angles
There are 15 sides
If the sum of the interior angles = 900 degrees, then it is a Heptagon and has seven sides. =] -ray
sum interior angles = (number of sides - 2) × 180° → number of sides = sum interior angles ÷ 180° + 2 = 5040° ÷ 180° + 2 = 30
Four sides
It will have 28 sides if its interior angles add up to 4680 degrees