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The sum of three consecutive odd integers, starting with N, is expressed as N + (N+2) + (N+4). If that sum is 363, then you have 3N + 6 = 363. Solve for N and you have 119.

Since N (119) is odd, the answer and question are valid. (If N had been even, the question would have been invalid, and the answer would have been meaningless. This test is simply a sanity check.) The three numbers are 119, 121, and 123.

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Q: The sum of three consecutive odd integers is 363 what are the numbers?

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Your question is not well formed, but i assume you mean 3 consecutive integers that sum to -363. If that is the case solve the following equation: (n-1) + (n) + (n+1) = -363 to give you the middle integer.

The numbers are 120, 121 and 122.

Factors of 363 = 1, 3, 11, 33, 121, 363.

There are infinitely many numbers. One pair, that is easy to remember, is 1 and 363.

3/11 of 363 is 99.

3

363 = 1 x 363, 3 x 121, 11 x 33.

The numbers below in parentheses are the factor pairs of 363. Multiplied together they will equal 363: (1, 363) (3, 121) (11, 33)

Any of its factors

Three hundred sixty-three.

167 363 429 512 579579 - 167 = 412Yes, the range of the set of numbers is 412.

You need at least two numbers to find a GCF.

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