Well, hot diggity dog! Let's break it down like a boss. If the sum of three consecutive odd integers is 363, then the middle number must be 121. Why? Because 121 is one-third of 363. So, the numbers are 119, 121, and 123. Bingo bango!
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The sum of three consecutive odd integers, starting with N, is expressed as N + (N+2) + (N+4). If that sum is 363, then you have 3N + 6 = 363. Solve for N and you have 119.
Since N (119) is odd, the answer and question are valid. (If N had been even, the question would have been invalid, and the answer would have been meaningless. This test is simply a sanity check.) The three numbers are 119, 121, and 123.
363 = 1 x 363, 3 x 121, 11 x 33.
The factors of 363 are: 1, 3, 11, 33, 121, 363
no 360 = 120 x 3 so 363 366 369 are multiples not 367
Oh, isn't that a happy little question! Let's take a moment to appreciate the number 363. It can be divided by 1, 3, 11, 33, 121, and 363. Each number is like a color on our palette, adding depth and beauty to the mathematical landscape. Just remember, there are no mistakes, only happy little divisions.
19.05255888325765 x 19.05255888325765 = 363