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The sum of three consecutive odd integers, starting with N, is expressed as N + (N+2) + (N+4). If that sum is 363, then you have 3N + 6 = 363. Solve for N and you have 119.
Since N (119) is odd, the answer and question are valid. (If N had been even, the question would have been invalid, and the answer would have been meaningless. This test is simply a sanity check.) The three numbers are 119, 121, and 123.

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15y ago

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