First number: x
Second: x+1
Third: x+2
x + x+1 + x+2 = 123,
3x + 3 = 123
x + 1 = 41
x = 40
x + 2 = 42
The numbers are: 40, 41, 42.
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The numbers are 40, 41 and 42.
between which two consecutive integers does the square root lie 123
The numbers are 122, 123, 124 as well as 121, 123, 125.
The numbers are 39, 41 and 43.
It can be, if the numbers are the right ones.