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The numbers are 15, 9, and 3.

Q: The sum of three numbers in AP is 27 and their product is 405 Find the numbers?

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I assume you mean to find the prime factorization of 405. If so: 34 x 5

405

To find the LCM of numbers you first need to break them down into their prime factors. In this case: 27=3x3x3 45=5x3x3 81=3x3x3x3 The next step is to disregard any duplicates when there are common prime factors. All numbers use two 3s so we can disregard 4 of them. Two numbers use an additional 3 so we can disregard 1 of them. This leaves us with: 5,3,3,3,3 Find the product of all of these numbers: 5x3x3x3=405 And that gives us the LCM. So the LCM of 27, 45, and 81 is 405.

1 x 405, 3 x 135, 5 x 81, 9 x 45, 15 x 27

The answer is 22. Start at the number 405, then every 9th number 594. Subtract 405 from 594 and you get 189. Then divide 189 by 9 and you get 21. Add the number 405. The answer you get is 22.

Related questions

In exponents: 34*5 = 405

GM of two numbers is the square root of their product, in this case sqrt 2025 ie 45.

405 = 3 x 3 x 3 x 3 x 5

634 multiplied by 405 is 256,770.

The prime numbers (factors) of 405 are: 3 and 5

The geometric mean is 45.0

I assume you mean to find the prime factorization of 405. If so: 34 x 5

405

The numbers that go into 405 are 1, 3, 5, 9, 15, 27, 45, 81, 135, and 405.

All multiples of 405, which is an infinite number.

The product is 81,000

To find the LCM of numbers you first need to break them down into their prime factors. In this case: 27=3x3x3 45=5x3x3 81=3x3x3x3 The next step is to disregard any duplicates when there are common prime factors. All numbers use two 3s so we can disregard 4 of them. Two numbers use an additional 3 so we can disregard 1 of them. This leaves us with: 5,3,3,3,3 Find the product of all of these numbers: 5x3x3x3=405 And that gives us the LCM. So the LCM of 27, 45, and 81 is 405.