Suppose the numbers are x and y.
The sum of their reciprocals = 1/x + 1/y
= y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
(50 + 15) = 65 (50 x 15) = 750 1/50 + 1/15 = 13/150
Two numbers with a product of 1 are called reciprocals. If you have a number and want to find the reciprocal of it, simply divide 1 by the number. For example, the reciprocal of 5 is 1/5, and the reciprocal of 700 is 1/700.
4 and -1 have a product of -4 and a sum of 3.
sannie
It is 0.5
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
No, the Sum of two reciprocals isn't 1. However, the PRODUCT of two reciprocals is 1. For example, if you multiply 1/2 with 2/1, you'd multiply the two numeraters, which would be 1X2=2, and the two denominators, which is 2X1=2. this would cause the answer to be 2/2, or 1.
The Two numbers are reciprocals of each number
I have a feeling that you wrote "opposite reciprocals"where you only needed to write "reciprocals".Their product is ' 1 '.
If you multiply two reciprocals, their product must be 1.
Yes.
12 and 18
The product of two mutual reciprocals is 1 .
(50 + 15) = 65 (50 x 15) = 750 1/50 + 1/15 = 13/150