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The sum of two numbers is 16 and the sum of their squares is 146 find the two numbers?
Wiki User
∙ 11y ago
So, 16-x=±√(146-x^2)
(16-x)^2=146-x^2
256-32x+x^2=146-x^2
2x^2-32x+110=0
x^2-16x+55=0
Quadratic formula:
x=[16±√(256-220)]/2
x=(16±6)/2
x=8±3
x=11 or x=5. Plug these values back into the original equations, and you will see that y also equals 11 or 5. So, the two pairs of numbers that satisfy the original equations are: x=11, y=5; and x=5, y=11
Wiki User
∙ 11y ago
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