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The sum of two numbers is 16 and the sum of their squares is 146 find the two numbers?
So, 16-x=±√(146-x^2)
(16-x)^2=146-x^2
256-32x+x^2=146-x^2
2x^2-32x+110=0
x^2-16x+55=0
x=[16±√(256-220)]/2
x=(16±6)/2
x=8±3
x=11 or x=5. Plug these values back into the original equations, and you will see that y also equals 11 or 5. So, the two pairs of numbers that satisfy the original equations are: x=11, y=5; and x=5, y=11
What else can I help you with?
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Sum of squares? Product?
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The sum of two positive numbers is 4 and the sum fo their cubes is 28 What is the sum of their squares?
The sum of their squares is 10.
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Explain the square of the sum of two numbers is different from the sum of the squares of two numbers?
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What are the numbers when the sum of two numbers is 22 and the sum of their squares is 250?
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Not unless at least one of the numbers is zero.
Difference between the sum of the squares and the square of the sums of n numbers?
Difference between the sum of the squares and the square of the sums of n numbers?Read more:Difference_between_the_sum_of_the_squares_and_the_square_of_the_sums_of_n_numbers
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85
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The sum of the squares of two consecutive positive numbers is 61. What is the number?
There is no single number here. The two seed numbers are 5 and 6; their squares sum to 61.
