The sum of two numbers is 22 and their product is 117 find the number?

Answer 1

Two equations are needed to solve for two variables, and we have them.

Let one number=x and the other=y

x+y=22 and x*y=117

subtract y from both sides and you get x=22-y

substituting (22-y) in for x gives (22-y)*y=117

after you distribute the y, 22y-y2=117

the easiest step would be to add y2 to both sides and subtract 22y from both sides

22y=117+y2 0=y2-22y+117 factor to (y-13)(y-9)=0 so y=13 or 9

One of the numbers is 13 and the other is 9

Answer 2

Let the two numbers be x and y. We know that x + y = 22 and xy = 117. From the first equation, we can express y in terms of x as y = 22 - x. Substituting this into the second equation gives us x(22 - x) = 117. Simplifying this equation gives us x^2 - 22x + 117 = 0. Solving this quadratic equation gives us x = 9 and x = 13. Therefore, the two numbers are 9 and 13.