I'll turn this into an algebra equation.
x=the second number.
x+(9+5x)=75
After solving for x, the solution turns out to be
x=11
If we put 11 in for x, it turns out to be equal.
Thus, the answer is 11.
a=58.4615 b=5.2308 c=41.3076
four times a number is 6 more than three times a second number while 8 times the first number is 22 less than 7 times the second number. find the 2 numbers
y = 3x+8 x + y = 72 x = 16 y = 56
You only have one math statement here. You can relate the two but you can not get the only solution. Let x=>the first number. Let y=>the second number y=3x+4 This can be graphed as a straight line with a slope of 3 and starting at 4.
Since the other two numbers depend on the first number, let the 1st = x. So the 2nd = 4x and the 3rd = x + 3. x + 4x + x + 3 = 81 6x + 3 = 81 6x = 78 x = 13 Thus the numbers are 13, 52 and 16.
a=58.4615 b=5.2308 c=41.3076
Take two numbers. Throw (the first number) into a box (the second number) times. The total amount in the box is then the product of the two numbers.
the sum of three numbers is 14.the first number minus three times the third number is the second number.the second number is six more than the first number.find the three numbers
four times a number is 6 more than three times a second number while 8 times the first number is 22 less than 7 times the second number. find the 2 numbers
The second is 12 more than the first. The second is 48% more than the first (or1.48 times the first).
y = 3x+8 x + y = 72 x = 16 y = 56
The numbers are 14, 16 and 18.
Two odd numbers are said to be consecutive if there are no other odd numbers in between. This happens when the first number is odd, and the second number is two more than the first number.
Without more information, there are an infinite number of solutions to this. 13, 52 and 1 20, 80 and 8 5, 20 and -7
You only have one math statement here. You can relate the two but you can not get the only solution. Let x=>the first number. Let y=>the second number y=3x+4 This can be graphed as a straight line with a slope of 3 and starting at 4.
Since the other two numbers depend on the first number, let the 1st = x. So the 2nd = 4x and the 3rd = x + 3. x + 4x + x + 3 = 81 6x + 3 = 81 6x = 78 x = 13 Thus the numbers are 13, 52 and 16.
The numbers are 29, 30, & 31. 29 * 4 = 116 ....... 31 * 3 = 93; 93 + 23 = 116