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669
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RossLet's denote the first even number as x. The next two consecutive even numbers would be x+2 and x+4. Adding these three numbers together, the equation would be x + (x+2) + (x+4) = 666. Simplifying this equation, we get 3x + 6 = 666. Solving for x, we find x = 220. Therefore, the three consecutive even numbers that add up to 666 are 220, 222, and 224.
Let the number be n, n+2, & n+4.
Hence
n + n+2 + n+4 = 666
3n + 6 = 666
3n = 660
n = 220
n+2 = 222
n+4 = 224
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What are four consecutive numbers that add up to 35?
There are no four consecutive whole numbers that add up to 35. The sum of two consecutive [whole] numbers is an even number plus an odd number which is an odd number. The sum of two consecutive numbers and the two next consecutive numbers is the sum of two odd numbers which is even, but 35 is odd, so no four consecutive whole numbers cannot add up to 35.
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If 4 consecutive even numbers add up to 100 what would be the largest of the 4 numbers?
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