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Call your number 10x + y. x = y + 2 and 10x + y = 4 + 6(x + y)

Substitute y + 2 for x: 10(y + 2) + y = 4 + 6((y + 2) + y)

This simplifies to 10y + 20 + y = 4 + 6y + 12 + 6y, ie 20 - 16 = 12y - 11y so y = 4 and x = 6

Your number is 64, which is indeed 4 more than the sum of its digits.

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Q: The tens digit of a two-digit number is 2 more than the units digit. the number is 4 more than 6 times the sum of the digits. find the number.?
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