Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
2,401
There are 4*4*3*2*1 = 96 such numbers.
Well honey, you've got 4 digits there, so you can form 4! (4 factorial) which is 24 numbers. That's right, you can make 24 different combinations with those digits. Math can be fun when you've got some sassy numbers to play with!
5^4
99999
There are 3,265,920 numbers that can be formed using all the digits. The answer to the question will depend on which one of these.
There are 60480 numbers.
There are 4^6 = 4096 such numbers.
Assuming that numbers with a leading zero is not permitted, the answer is 9*9! = 3,265,920. If leading 0s were permitted, the answer would have been 3,628,800
8.
If the digits are all different then 18. Otherwise, 192.
There are 900 of them.
15 of them.
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
27
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77