How about "is always zero"?
y = -4x
No, a circle can never pass through three points of a straight line. The circle will touch 1) no points of the line, 2) one point of the line (which is now tangent to the circle), or 3) two points of the line. A line can contain (at most) twopoints that lie on the line.
it will never be a vertical line as the slope is velocity and that would be infinite speed
It is a straight line through the origin, with a positive slope.It is a straight line through the origin, with a positive slope.It is a straight line through the origin, with a positive slope.It is a straight line through the origin, with a positive slope.
Izzy and Amie made the zero with a line through it!
y = -4x
No. The y axis passes through the origin but its slope is not defined.
where thair located on the number line or where the orgin + a-t-e
That line is commonly, and correctly, referred to as the 'y-axis'.
the answer is always
A transversal line cutting through parallel lines creates various angles
Of course it can and it does: it is the x-axis.
No, a circle can never pass through three points of a straight line. The circle will touch 1) no points of the line, 2) one point of the line (which is now tangent to the circle), or 3) two points of the line. A line can contain (at most) twopoints that lie on the line.
It can be but in general a reflection in a line produces a 'mirror image'
A never ending line goes to infinity, so that line is called Infinite.
A line.
To write a linear equation that passes through the origin, you can use the slope-intercept form, which is ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Since the line passes through the origin, the y-intercept ( b ) is 0, simplifying the equation to ( y = mx ). You can choose any value for the slope ( m ) to define the steepness of the line. For example, if you choose ( m = 2 ), the equation would be ( y = 2x ).