Three consecutive even integers whose sum is 48?

Answer 1

Let the first even number be x. So the second even number will be x + 2, and the third even number will be x + 4. So,

x + (x + 2) + (x + 4) = 48

3x + 6 = 48 subtract 6 to both sides;

3x = 42 divide by 3 to both sides;

x = 14, the first number;

x + 2 = 14 + 2 = 16, the second number;

x + 4 = 14 + 4 = 18, the third number.

Check.