x + x + 2 + x + 4 +x + 6 = 336
4x + 12 = 336
4x = 324
x = 81
81,83,85, 87
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The integers are 17, 19, 21 and 23.
17 , 19 , 21 and 23 are the odd integers whose sum is 80 and the least integer is 17
The sum is four.
Heading upwards from -3, the four consecutive integers are -3, -1, 1, 3.-3, -1, 1 and 3.
There is no set of two consecutive odd integers for 323. The set has one odd and one even integer. The numbers are 161 and 162.
There are four consecutive odd integers: 81, 83, 85 and 87.
The integers are 81, 83, 85 and 87.
The sum of any three consecutive odd integers is going to give an odd result. It is impossible for the sum of an odd number of odd integers to equal an even number.
There is no set of four consecutive odd integers for 204. The only set is even: 48, 50, 52 and 54.
The four consecutive odd integers are 43 + 45 + 47 + 49 = 184
They are odd consecutive integers: 21, 23, 25 and 27.
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
Any odd integer can be represented as 2n+1, where n is any integer. The integers, starting with one, always proceed as odd, even, odd, even, etc. Therefore, a consecutive odd would be two more than the first. So 2n+1, 2n+3, 2n+5, and 2n+7 summed to 336. Simple algebra gives n=40, and the four numbers as 81, 83, 85, and 87.
No.
The integers are 51, 53, 55 and 57.
This is not possible. Four odd integers, consecutive or otherwise, MUST total an even number eg 5 + 7 + 9 + 11 = 32
The numbers are 51, 53, 55 and 57.