s(8+t)
A series of transformations on quadrilateral S resulted in quadrilateral T. The angles of quadrilateral S and T are congruent but the sides of quadrilateral T are twice as long as quadrilateral S. Which transformation on quadrilateral S must be included to result in quadrilateral T * sorry thats the full question!
8t
13 + T >= 24 T >= 11 T is at least 11.
2x-5 is twice a number decreased by 5.
2t+3
s(8+t)
Sexually Malested And Raped Twice S M A R T
A series of transformations on quadrilateral S resulted in quadrilateral T. The angles of quadrilateral S and T are congruent but the sides of quadrilateral T are twice as long as quadrilateral S. Which transformation on quadrilateral S must be included to result in quadrilateral T * sorry thats the full question!
int Nodes (Tree *t) { int sum= 0; if (t) { sum+=1; if (t->left) sum += Nodes (t->left); if (t->right) sum += Nodes (t->right); } return sum; }
2x-5 is twice a number decreased by 5.
#include #include void main(){long n,s=0,t,d;clrscr();cout > n;t=n;while(n>0){d=n%10;s=s+d;n=n/10;}cout
#include<stdio.h> #include<conio.h> main() { int n,s,r,t; clrscr(); printf("enter n"); scanf("%d",&n); s=0;t=0; while(n!=0) { r=n%10; { if(r%2!=0) t=t+r; if(r%2==0) s=s+r; } n=n/10; } printf("sum of even position digits%d\n",s); printf("sum of odd position digits%d\n",t); getch(); }
t-j. Happy Christmas!
T
t+31
The sum of the numbers in the nth row of Pascal's triangle is equal to 2^n. Therefore, the sum of the numbers in the 100th row of Pascal's triangle would be 2^100. This formula is derived from the properties of Pascal's triangle, where each number is a combination of the two numbers above it.