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Two numbers have a sum of 70 and a product of 1189 What are the numbers?
Wiki User
∙ 16y ago
41, 29 Set up using algebraic equations: x + y = 70 x*y = 1189 Solve simultaneously by rearranging the first equation to y = 70 - x and substitute this value for y into the second equation to get: x * (70 - x) = 1189, which rearranged is x2-70x+1189 Use the quadratic equation to find the two values of x. x = (-b ± √(b2 - 4ac)) / 2a where a,b,c are the coefficeints of the quadratic equation in the form of ax2 + bx + c
Wiki User
∙ 16y ago
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