2*84 3*56 4*42 6*28 7*24 8*21 12*14
39 and 84.
21 and 4 14 and 6 28 and 3 12 and 7 42 and 2
5
How about: 4*21 = 84
12x2x2x2
109
The answer is 🙈🙉🙊
You'll need four. 2 x 3 x 3 x 7 = 84
There are many equations that equal 84. 14 multiplied by 6 is equal to 84. 7 multiplied by 12 is also equal to 84.
The numbers below are the factor pairs of 84 (multiplied together they equal 84): (1, 84) (2, 42) (3, 28) (4, 21) (6, 14) (7, 12)
There are infinitely many pairs. Two pairs, for example, are (1, 84) and (10, 8.4).
How about: 5*84 = 420 as one example
8 and 4, added together and multiplied by 7
2*84 3*56 4*42 6*28 7*24 8*21 12*14
No. In order for two factors (i.e. two numbers multiplied together) to result in an even number, at least one of the factors must be even. Except for "2" all prime numbers by definition must be odd numbers. 168/2 = 84. 84 is not prime. Therefore you are looking for 2 odd factors of 168. But this is a fruitless search as 2 odd numbers multiplied together will never result in an even number.
124