Theorem: If two similar triangles have a scalar factor a : b, then the ratio of their perimeters is a : b
By the theorem, the ratio of the perimeters of the similar triangles is 2 : 3.
For rectangles, perimeter is 2*(L1 + W1). If the second rectangle's sides are scaled by a factor S, then its perimeter is 2*(S*L1 + S*W1) = S*2*(L1 + W1), or the perimeter of the first, multiplied by the same factor S.
In general, if an N-sided polygon has sides {x1, x2, x3....,xN}, then its perimeter is x1 + x2 + x3 + ... + xN. If the second similar polygon (with each side (labeled y, with corresponding subscripts) scaled by S, so that y1 = S*x1, etc. The perimeter is y1 + y2 + ... + yN = S*x1 + S*x2 + ... + S*xN = S*(x1 + x2 + ... + xN ),
which is the factor S, times the perimeter of the first polygon.
4.9
The perimeters of two similar polygons have the same ratio as the measure of any pair of corresponding sides. So the ratio of the measure of two corresponding sides of two similar kites with perimeter 21 and 28 respectively, is 21/28 equivalent to 3/4.
If you are trying to find the ratio of the lengths of two similar rectangles, divide the length of one side of one rectangle by the corresponding side length of the other rectangle. To find the ratio between their volumes, divide the volume of one rectangle by the volume the other rectangle. To find volume, multiply the width of the rectangle by the length of the rectangle.
The ratio for 3 thirds is simply 1/2, the 2 being the 2 thirds, and the 1 being the rest.
It is: 2/3 is the same as 4/6
The ratio of their perimeters is also 45/35 = 9/7. The ratio of their areas is (9/7)2 = 81/63
Their perimeters are in the same ratio.
The ratio of 25-ft to 20-ft is 5/4 or 1.25 .But ... knowing the perimeters alone is not enough informationto guarantee that the two figures are similar.-- They could be two rectangles, one measuring 25-ft by 1-ft, the other measuring 4-ft by 5-ft.Those are not similar rectangles.-- They could even be one rectangle and one triangle ... definitely not similar.
The ratio of their perimeters will be 3:1, while the ratio of their areas will be 9:1 (i.e. 32:1)
4.9
No, in general that is not true. For two similar figures it is true. But you can easily design two different figures that have the same perimeters and different areas, or the same area and different perimeters. For example, two rectangles with a different length-to-width ratio.
I guess you mean the ratio of the areas; it depends if the 2 rectangles are "similar figures"; that is their matching sides are in the same ratio. If they are similar then the ratio of their areas is the square of the ratio of the sides.
If two similar rectangles have the widths 16m and 14cm what is the ratio of the perimiters?
If two rectangles are similar, they have corresponding sides and corresponding angles. Corresponding sides must have the same ratio.
Whatever the ratio of perimeters of the similar figures, the areas will be in the ratios squared. Examples: * if the figures have perimeters in a ratio of 1:2, their areas will have a ratio of 1²:2² = 1:4. * If the figures have perimeters in a ratio of 2:3, their areas will have a ratio of 2²:3² = 4:9.
The perimeters of two similar polygons have the same ratio as the measure of any pair of corresponding sides. So the ratio of the measure of two corresponding sides of two similar kites with perimeter 21 and 28 respectively, is 21/28 equivalent to 3/4.
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?