The ratio of their perimeters is also 45/35 = 9/7.
The ratio of their areas is (9/7)2 = 81/63
The ratio of their perimeters will be 3:1, while the ratio of their areas will be 9:1 (i.e. 32:1)
Their perimeters are in the same ratio.
It is 0.6046 : 1 (approx).
If lengths are in the ratio a:b, then areas are in the ratio a2:b2 since area is length x length. If areas are in the ratio c:d, then lengths are in the ration sqrt(c):sqrt(d). Areas of decagons are 625sq ft and 100 sq ft, they are in the ratio of 625:100 = 25:4 (dividing through by 25 as ratios are usually given in the smallest terms). Thus their lengths are in the ratio of sqrt(25):sqrt(4) = 5:2 As perimeter is a length, the perimeters are in the ratio of 5:2.
If two rectangles are similar, they have corresponding sides and corresponding angles. Corresponding sides must have the same ratio.
The ratio of their perimeters will be 3:1, while the ratio of their areas will be 9:1 (i.e. 32:1)
I guess you mean the ratio of the areas; it depends if the 2 rectangles are "similar figures"; that is their matching sides are in the same ratio. If they are similar then the ratio of their areas is the square of the ratio of the sides.
Their perimeters are in the same ratio.
No, in general that is not true. For two similar figures it is true. But you can easily design two different figures that have the same perimeters and different areas, or the same area and different perimeters. For example, two rectangles with a different length-to-width ratio.
Whatever the ratio of perimeters of the similar figures, the areas will be in the ratios squared. Examples: * if the figures have perimeters in a ratio of 1:2, their areas will have a ratio of 1²:2² = 1:4. * If the figures have perimeters in a ratio of 2:3, their areas will have a ratio of 2²:3² = 4:9.
The ratio of 25-ft to 20-ft is 5/4 or 1.25 .But ... knowing the perimeters alone is not enough informationto guarantee that the two figures are similar.-- They could be two rectangles, one measuring 25-ft by 1-ft, the other measuring 4-ft by 5-ft.Those are not similar rectangles.-- They could even be one rectangle and one triangle ... definitely not similar.
4.9
The ratio is 16 to 81.
If two similar rectangles have the widths 16m and 14cm what is the ratio of the perimiters?
It is 0.6046 : 1 (approx).
is it 3:5 and 3:5
If lengths are in the ratio a:b, then areas are in the ratio a2:b2 since area is length x length. If areas are in the ratio c:d, then lengths are in the ration sqrt(c):sqrt(d). Areas of decagons are 625sq ft and 100 sq ft, they are in the ratio of 625:100 = 25:4 (dividing through by 25 as ratios are usually given in the smallest terms). Thus their lengths are in the ratio of sqrt(25):sqrt(4) = 5:2 As perimeter is a length, the perimeters are in the ratio of 5:2.