4x7=28 2(4x7)=2x28=56
It is a simple linear equation in 's'. Its solution is the number that 's' must bein order to make it a true statement. The solution may be found like this:4s + 10 = 2s + 2Subtract 10 from each side of the equation:4s = 2s - 8Subtract 2s from each side:2s = -8Divide each side by 2 :s = -4
it shows the number of something...MISSISSIPPIM-1I-4S-4P-2
-2/2-2/2 = -2
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(4+4)+(4/4)+(4/4)
All p orbitals are the same - px, py, pz - 2 electrons in each, 6 in a p orbital in total.
A Ca atom in its 4s^2 electron configuration can make up to 2 bonds without hybridization. This is because it has two unpaired electrons in its 4s orbital available for bonding.
1s electrons = 2 2s electrons = 2 3s electrons = 2 4s electrons = 2 so a total of 8
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Calcium is the element that has 2 electrons in the 4s sublevel.
4x7=28 2(4x7)=2x28=56
4s^2 + s - 14 = (4s - 7)(s + 2)
(4s + 1)(4s + 1) or (4s + 1)2
There are 18 electrons in total, and the outer energy levels are the 4s and 3d orbitals. Therefore, there are 2 electrons in the 4s orbital and 4 electrons in the 3d orbital, making a total of 6 electrons in the outer energy levels.
Use the four 4's in the following ways: 4 + 4 = 8 8/4 = 2 2 + 4 = 6. Therefore, ((4 + 4)/4) + 4 = 6
The 4s orbital can hold a maximum of 2 electrons.