15 m
radius = diameter ÷ 2 volume cylinder = area of end × height → volume = π × radius² × height → volume = π × (diameter ÷ 2)² × height →volume = π × (6m ÷ 2)² × 3 m → volume = 27π m³ ≈ 27 × 3.14 m³ = 84.78 m³ ≈ 84.8 m³ to 1 dp.
surface area = 4πr² → r = √(A/4π) = √(36π m²/4π) = √(9 m²) = 3 m volume = (4/3)πr³ = (4/3)π(3 m)³ = (4/3)π27 m³ = 36π m³
Volume of each can = (pi) R2 H = (pi) (6)2 (15) = 540 pi cm3Volume of the tank = 3 x 2 x 1.5 = 9 m3 = 9 x 106 cm3IF the tank is full when you begin, and you don't spill any, then you can fill9 x 106 / 540 pi = 5,305 cans, with 279.5 cm3 (0.165 can) left over.
Volume of a sphere is 4/3 pi times the cube of its radius.
15 cu m
It is 4 m because 4*4*4 = 64 cubic m
Volume of the pyramid: 1/3*base area*height in cubic m
15 m
Volume of a rectangular solid is the product of its length, breadth and heigth. Volume= 7x8x4= 224 cubic metres.
For the US Army, the average combat medium tank was 1. 6 tons WW1 M1917 Renault Tank 2. 30 tons WW2 M-4 Sherman Tank 3. 52 tons Vietnam War M-48 Patton Tank (Vietnam War: 17 tons M-551 Sheridan Light Tank) 4. 67 tons M-1 Abrams Tank
radius = diameter ÷ 2 volume cylinder = area of end × height → volume = π × radius² × height → volume = π × (diameter ÷ 2)² × height →volume = π × (6m ÷ 2)² × 3 m → volume = 27π m³ ≈ 27 × 3.14 m³ = 84.78 m³ ≈ 84.8 m³ to 1 dp.
For the US Army, the average combat medium tank was: 1. 6 tons WW1 M1917 Renault Tank 2. 30 tons WW2 M-4 Sherman Tank 3. 52 tons Vietnam War M-48 Patton Tank (Vietnam War: 17 tons M-551 Sheridan Light Tank) 4. 67 tons M-1 Abrams Tank
Both atom and its nucleus are considered to be spherical. Hence using the formula 4/3 pi r3 we can find the volume. In case of atom r would be of the order of 10-11 m and that for nucleus it is of the order of 10-15 m
It is: 10*5*5 = 250 cubic m
surface area = 4πr² → r = √(A/4π) = √(36π m²/4π) = √(9 m²) = 3 m volume = (4/3)πr³ = (4/3)π(3 m)³ = (4/3)π27 m³ = 36π m³
Volume = Length*Height*Width = (3/m)*x*m = 3xTherefore 4 = 3x so that x = 4/3.