Stating that it is an equilateral triangle, we are told that all sides are equal.This is another way of saying:4x - y = 7and2x + 3y = 7So this can be solved by eliminating one of those variables:2x + 3y = 7x = (7 - 3y) / 24((7 - 3y) / 2) - y = 714 - 7y = 7y = 1x = 2
4x + 7 = 6x -7 14=2x so x = 7 (plus a negative # is simply - that number)
If 4x + 7 = 3... then x must equal -1
4x - 7 = 5 + 7x x = -4
-3y + 6 = 7 Therefore, -3y = 1 Therefore, y = 1/-3 Therefore, y = -0.3 recurring (that is, -0.3333...)
4x + 3y = 7 y = [(-4)/3] x + 7/3
4x - 3y = -7 Change all signs: -4x + 3y = 7 Add 4x to both sides: 3y = 4x + 7 Divide both sides by 3: y = (4/3)*x + 7/3 m = 4/3, b = 7/3
You need to organise your question properly. 3x+2y=4 4x + 3y= 7? Is 4 4x = 44x or 4-4x or 4+4x How can there be 2 equal signs in 1 equation?
given is that 4x+3y=6(3x+3y)=7 i.e., 6(3x+3y)=7 &&& 4x+3y=7 ---------------(1) 3x+3y=7/6 x+y=7/18 _________(2) multiply eqn(2) by 4 4x+4y=28/18 -------------------------(3) (3)-(1) 4x+3y-4x-4y=7-(28/18) y= -98/18 substitute y in eqn(2) x-98/18=7/18 x=7/18+98/18 x=105/18. therefore x=105/18 : y= -98/18
(A): 4x + y = 7 (B): 2x - 3y = -7 2*(B) 4x - 6y = -14 Subtract from (A) 7y = 21 Divide both sides by 7: y = 3 Substitute in (A): 4x + 3 = 7 ie 4x = 4 or x = 1 Answer: x = 1 , y = 3
7
Yes and their solutions are x = 41 and y = -58
16x2 + 8x + 1 - 9y2 = (4x + 1)2 - (3y)2 which is a difference of two squares. = (4x + 1 + 3y)*(4x + 1 - 3y)
They are simultaneous equations and their solutions are x = 41 and y = -58
Stating that it is an equilateral triangle, we are told that all sides are equal.This is another way of saying:4x - y = 7and2x + 3y = 7So this can be solved by eliminating one of those variables:2x + 3y = 7x = (7 - 3y) / 24((7 - 3y) / 2) - y = 714 - 7y = 7y = 1x = 2
(1) x+y=15(2) 4x+3y=38From (1) one gets x=15 -y, put into(2)4(15-y)+3y=3860-4y+3y=3860-y=38y=22 then x=15-y=-7(-7,22) is the solution
x+y=15, or y=15-x4x+3y=38Substitute y in 2nd equation with 15-x:4x+45-3x=38x=-7y=15-(-7)=22(-7,22)