Well, honey, the numbers divisible by both 4 and 6 are multiples of their least common multiple, which is 12. So, any number that can be divided by 12 without leaving a remainder is your answer. Now, go forth and conquer those divisible numbers like the math whiz you are!
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Oh, dude, numbers divisible by both 4 and 6 are like the VIPs of the math world. So, the numbers that fit the bill are basically the common multiples of 4 and 6. That's like the cool kids club where 24, 48, 72, and so on get to hang out. Just think of them as the ultimate math squad, always dividing and conquering together.
Numbers that are divisible by both 4 and 6 must be multiples of the least common multiple of 4 and 6, which is 12. Therefore, numbers divisible by both 4 and 6 are any multiples of 12. In other words, any number that can be expressed as 12 multiplied by an integer (e.g., 12, 24, 36, 48, etc.) will be divisible by both 4 and 6.
Numbers that are divisible by both 6 and 7 must be divisible by the least common multiple of 6 and 7, which is 42. Therefore, the numbers divisible by both 6 and 7 are multiples of 42. This includes numbers like 42, 84, 126, and so on.
76 is divisible by some of those numbers, but not all of them. 76 is an even number that ends in 6. It is divisible by 2. The sum of the digits of 76 (13) is not evenly divisible by 3. 76 is not divisible by 3. 4 times 19 is 76. 76 is divisible by 4. Only numbers that end in 0 and 5 are divisible by 5. 76 is not divisible by 5. 6 and 9 do not divide evenly into 76, so 76 is not divisible by 6 and 9. Only numbers that end in 0 are divisible by 10. 76 is not divisible by 10. Of the numbers listed, 76 is only divisible by 2 and 4.
Numbers that are divisible by both 6 and 8 must be multiples of the least common multiple of 6 and 8, which is 24. Therefore, numbers that are divisible by both 6 and 8 are any multiples of 24. These numbers include 24, 48, 72, 96, and so on.
They are divisible by 2, 3, 4, 5, 6, 10, 12, 15, 30 and 60 at least.
Four. 24 and its multiples.