20 ft.
measure the length and the width
A small rectangular box!
When you want to build a fence around your house, you need to know the perimeter.
Metre.
20 ft.
37
16 feet
16 feet
16 feet.
Length + width = half of perimeter so width = p/2 - length ie (22-12) 10 yards.
measure the length and the width
Change the perimeter to feet and let the width be x. Perimeter = 2(22+x) = 76 feet 44+2x = 76 2x = 76-44 2x = 32 x = 16 So the width is 16 feet and the length is 22 feet Check: 16+16+22+22 = 76 feet
(The perimeter is the outside length around an object other than circular ones. It can also mean a guarded area around a location.)For quadrilaterals, the perimeter is twice the length plus twice the width.The garden club planted flowers around the perimeter of the plaza.The police set up a perimeter around the crime scene to search for the suspect.There are constant patrols around the perimeter of the army base.
The house is 30 ft wide. Perimeter of a rectanglw is 2L + 2W. solved: P = 2L + 2W (convert P to ft and sub known values) 132 = (2*36) + 2W (simplify) 132 = 72 + 2W (subtract 72 from each side of the equation) 60 = 2W (divide both sides of the equation by 2 to find the width) 30 = W
First find the length of this very very small house and let the length be x: Perimeter = 2(x+25) = 122 inches 2x+50 = 122 2x = 122-50 2x = 72 x = 36 So the length = 36 inches Area = 36*25 = 900 square inches
44 sq yd = 396 sq ft, so width = 396/36 = 11 ft