The house is 30 ft wide. Perimeter of a rectanglw is 2L + 2W. solved: P = 2L + 2W (convert P to ft and sub known values) 132 = (2*36) + 2W (simplify) 132 = 72 + 2W (subtract 72 from each side of the equation) 60 = 2W (divide both sides of the equation by 2 to find the width) 30 = W
What is the answer ?
Length + width = half of perimeter so width = p/2 - length ie (22-12) 10 yards.
38 x 44
The length of the rectangle is 27 meters and the width is 19 meters.
the perimeter of a rectangular rug is 40 ft. the length is 2 ft longer than the width. find the dimensions
length = 22 meters and width = 6 meters
40
width*height*length=perimeter of a rectangular prism! :)
Length + width = half of perimeter so width = p/2 - length ie (22-12) 10 yards.
37
20 ft.
Doubling the width of a rectangular rug will affect the perimeter because the total length and width will be doubled. The area will be twice the length times the width.
It is 2*(Length + Width).
Twice the (width plus length)
16 feet
16 feet
Perimeter=24ft
16 feet.