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In an isosceles triangle one base angle equals 73 find the size of the vertex angle?
jaj no se kompas jaj
When the vertex angle and the base of an isosceles triangle are given how do you find its area?
Let's A and x represent the given vertex angle and the base, respectively.Use the law of cosine to find the length of the legs of the triangle by doing x2 = m2 + n2 - 2mncos A, where m and n are the legs. Since the triangle is isosceles, m = n and therefore x2 = 2m2 - 2m2cos A. Solving for m gives m = sqrt(x2/(2 - cos A))Get the height of the triangle by using Pythagorean theorem. m2 = x2 + h2, where h is the height.Finally, get the area using the formula for a triangle's area, which is (base * height) / 2.
How do you find the equation of a parabola if you know the vertex and a point it passes through?
Use this form: y= a(x-h)² + k ; plug in the x and y coordinates of the vertex into (h,k) and then the other point coordinates into (x,y) and solve for a.
The vertex of the parabola below is at the point (-4-2) which equation below could be one for parabola?
-2
How do you find the vertex of an equation in vertex form?
look for the interceptions add these and divide it by 2 (that's the x vertex) for the yvertex you just have to fill in the x(vertex) however you can also use the formula -(b/2a)
