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Let's A and x represent the given vertex angle and the base, respectively.Use the law of cosine to find the length of the legs of the triangle by doing x2 = m2 + n2 - 2mncos A, where m and n are the legs. Since the triangle is isosceles, m = n and therefore x2 = 2m2 - 2m2cos A. Solving for m gives m = sqrt(x2/(2 - cos A))Get the height of the triangle by using Pythagorean theorem. m2 = x2 + h2, where h is the height.Finally, get the area using the formula for a triangle's area, which is (base * height) / 2.
Use this form: y= a(x-h)² + k ; plug in the x and y coordinates of the vertex into (h,k) and then the other point coordinates into (x,y) and solve for a.
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look for the interceptions add these and divide it by 2 (that's the x vertex) for the yvertex you just have to fill in the x(vertex) however you can also use the formula -(b/2a)