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what Given △ABC is isosceles with vertex ∠C. If m∠A= 3x-6 and m∠C=2x. Solve for x and find m∠?
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In an isosceles triangle one base angle equals 73 find the size of the vertex angle?
jaj no se kompas jaj
When the vertex angle and the base of an isosceles triangle are given how do you find its area?
Let's A and x represent the given vertex angle and the base, respectively.Use the law of cosine to find the length of the legs of the triangle by doing x2 = m2 + n2 - 2mncos A, where m and n are the legs. Since the triangle is isosceles, m = n and therefore x2 = 2m2 - 2m2cos A. Solving for m gives m = sqrt(x2/(2 - cos A))Get the height of the triangle by using Pythagorean theorem. m2 = x2 + h2, where h is the height.Finally, get the area using the formula for a triangle's area, which is (base * height) / 2.
How do you find the equation of a parabola if you know the vertex and a point it passes through?
Use this form: y= a(x-h)² + k ; plug in the x and y coordinates of the vertex into (h,k) and then the other point coordinates into (x,y) and solve for a.
How do you find the vertex of an equation in vertex form?
look for the interceptions add these and divide it by 2 (that's the x vertex) for the yvertex you just have to fill in the x(vertex) however you can also use the formula -(b/2a)
If the vertex angle of an isosceles triangle has a measure of 108 what is the base angle?
In an isosceles triangle two of the sides are equal, as well as two of the angles. Because a triangle's interior angles add up to 180, only one angle could be 108, therefore the other two angle must be equal. To find the measure of the other two angles 180 - 108 = 72/2 = 36.
How do you construct an isosceles triangle when base and angle at the vertex is given?
First find 180 minus the vertex angle and divide that by 2 to get the other angles. Then solve the other sides by using sin(vertex angle)/base=sin(other angles)/other sides.
The equal angles of an isosceles triangle?
To find the equal angels, base angles, of an isosceles triangle and you know the vertex angle, 180-vertex angle and then divide by two.
The vertex angle of an isosceles triangle is twice as large as one of the base angles Find the measure of the vertex angle?
90 degrees. This is an isosceles right triangle, standing on its hypotenuse.
A base angle of an isosceles triangle is 6 degrees more than the vertex angle. Find the vertex angle?
56 degrees
An exterior angle at the base of an isosceles triangle measures 110 find the measure of the vertex angle?
40
An exterior angle at the base of an isosceles triangle measures 130 find the measure of the vertex angle?
80 degrees.
In an isosceles triangle one base angle equals 73 find the size of the vertex angle?
jaj no se kompas jaj
Find length of the base if perimeter of an isosceles triangle is 70 in?
That's not enough information to solve the problem.
When the vertex angle and the base of an isosceles triangle are given how do you find its perimeter?
Using the trigonometry ratio for the cosine and by halving the base lenght which will result in two right angled triangles. Then after working out the hypotenuse simply double it and add on the original base length.
How can you find the area of an isosceles triangle when only given the base?
You can't. It is impossible.
When the vertex angle and the base of an isosceles triangle are given how do you find its area?
Let's A and x represent the given vertex angle and the base, respectively.Use the law of cosine to find the length of the legs of the triangle by doing x2 = m2 + n2 - 2mncos A, where m and n are the legs. Since the triangle is isosceles, m = n and therefore x2 = 2m2 - 2m2cos A. Solving for m gives m = sqrt(x2/(2 - cos A))Get the height of the triangle by using Pythagorean theorem. m2 = x2 + h2, where h is the height.Finally, get the area using the formula for a triangle's area, which is (base * height) / 2.
How do find the legs of an isosceles triangle if the area is given?
You cannot since there is not sufficient information.
