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In an isosceles triangle one base angle equals 73 find the size of the vertex angle?
jaj no se kompas jaj
When the vertex angle and the base of an isosceles triangle are given how do you find its area?
Let's A and x represent the given vertex angle and the base, respectively.Use the law of cosine to find the length of the legs of the triangle by doing x2 = m2 + n2 - 2mncos A, where m and n are the legs. Since the triangle is isosceles, m = n and therefore x2 = 2m2 - 2m2cos A. Solving for m gives m = sqrt(x2/(2 - cos A))Get the height of the triangle by using Pythagorean theorem. m2 = x2 + h2, where h is the height.Finally, get the area using the formula for a triangle's area, which is (base * height) / 2.
How do you find the equation of a parabola if you know the vertex and a point it passes through?
Use this form: y= a(x-h)² + k ; plug in the x and y coordinates of the vertex into (h,k) and then the other point coordinates into (x,y) and solve for a.
The vertex of the parabola below is at the point (-4-2) which equation below could be one for parabola?
-2
How do you find the vertex of an equation in vertex form?
look for the interceptions add these and divide it by 2 (that's the x vertex) for the yvertex you just have to fill in the x(vertex) however you can also use the formula -(b/2a)
How do you construct an isosceles triangle when base and angle at the vertex is given?
First find 180 minus the vertex angle and divide that by 2 to get the other angles. Then solve the other sides by using sin(vertex angle)/base=sin(other angles)/other sides.
The equal angles of an isosceles triangle?
To find the equal angels, base angles, of an isosceles triangle and you know the vertex angle, 180-vertex angle and then divide by two.
The vertex angle of an isosceles triangle is twice as large as one of the base angles Find the measure of the vertex angle?
90 degrees. This is an isosceles right triangle, standing on its hypotenuse.
A base angle of an isosceles triangle is 6 degrees more than the vertex angle. Find the vertex angle?
56 degrees
An exterior angle at the base of an isosceles triangle measures 110 find the measure of the vertex angle?
40
An exterior angle at the base of an isosceles triangle measures 130 find the measure of the vertex angle?
80 degrees.
How do you solve isosceles trapezoid median is given?
To solve for the dimensions of an isosceles trapezoid when the median is given, first recall that the median (or midsegment) of an isosceles trapezoid is the average of the lengths of the two parallel bases. If the median is ( m ) and the lengths of the bases are ( a ) and ( b ), then the relationship can be expressed as ( m = \frac{a + b}{2} ). You can use this equation to find one base if the other is known, or to establish relationships between the bases if additional information is provided. Additionally, you can apply properties of the trapezoid and the Pythagorean theorem to find heights or side lengths if needed.
In an isosceles triangle one base angle equals 73 find the size of the vertex angle?
jaj no se kompas jaj
When the vertex angle and the base of an isosceles triangle are given how do you find its perimeter?
Using the trigonometry ratio for the cosine and by halving the base lenght which will result in two right angled triangles. Then after working out the hypotenuse simply double it and add on the original base length.
Find length of the base if perimeter of an isosceles triangle is 70 in?
That's not enough information to solve the problem.
How can you find the area of an isosceles triangle when only given the base?
You can't. It is impossible.
When the vertex angle and the base of an isosceles triangle are given how do you find its area?
Let's A and x represent the given vertex angle and the base, respectively.Use the law of cosine to find the length of the legs of the triangle by doing x2 = m2 + n2 - 2mncos A, where m and n are the legs. Since the triangle is isosceles, m = n and therefore x2 = 2m2 - 2m2cos A. Solving for m gives m = sqrt(x2/(2 - cos A))Get the height of the triangle by using Pythagorean theorem. m2 = x2 + h2, where h is the height.Finally, get the area using the formula for a triangle's area, which is (base * height) / 2.
