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look for the interceptions add these and divide it by 2 (that's the x vertex) for the yvertex you just have to fill in the x(vertex) however you can also use the formula -(b/2a)

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The vertex of the parabola below is at the point (-4-2) which equation below could be one for parabola?

-2


How do you find other points on the parabola?

To find other points on a parabola, you can use its equation, typically in the form (y = ax^2 + bx + c). By selecting different values for (x) and substituting them into the equation, you can calculate the corresponding (y) values. Alternatively, you can also use the vertex form, (y = a(x-h)^2 + k), where ((h, k)) is the vertex, to find points by choosing (x) values around the vertex. Plotting these points will help visualize the shape of the parabola.


The vertex of the parabola below is at the point -3 -5 Which of the equations below could be the equation of this parabola?

2


How do you find the equation of a parabola if you know the vertex and a point it passes through?

Use this form: y= a(x-h)² + k ; plug in the x and y coordinates of the vertex into (h,k) and then the other point coordinates into (x,y) and solve for a.


How do you find the x value of the vertex of a quadratic equation?

It depends on the level of your mathematical knowledge. One way is to differentiate the quadratic equation and find the value of x for which the derivative is 0. The advantage of this method is that it works for turning points of polynomials of all degrees. The disadvantage is that you need to know differentiation. For a quadratic, an alternative, and simpler way is to write the equation in the form: y = ax2 + bx + c Then the x value of the vertex is -b/2a

Related Questions

What is the vertex form of a quadratic function and how do you find the vertex when a quadratic is in vertex form?

The vertex form of a quadratic function is expressed as ( f(x) = a(x-h)^2 + k ), where ( (h, k) ) represents the vertex of the parabola. To find the vertex when a quadratic is in vertex form, simply identify the values of ( h ) and ( k ) from the equation. The vertex is located at the point ( (h, k) ).


What is the equation for vertex form?

The vertex form for a quadratic equation is y=a(x-h)^2+k.


How do you find the vertex of an equation in standard form?

To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).


How do you find the vertex of a parabola when the equation is in standard form?

To find the vertex of a parabola in standard form, which is given by the equation ( y = ax^2 + bx + c ), you can use the formula for the x-coordinate of the vertex: ( x = -\frac{b}{2a} ). Once you have the x-coordinate, substitute it back into the original equation to find the corresponding y-coordinate. The vertex will then be at the point ( (x, y) ).


How do you write y equals x minus 4 x plus 2 in vertex form and find the vertex?

The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.


The vertex of the parabola below is at the point (-4-2) which equation below could be one for parabola?

-2


The vertex form of the equation of a parabola is y x-5 2 plus 16 what is the standard form of the equation?

In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.


What is the vertex form of y -4x2-6x?

The question does not contain an equation: only an expression. An expression cannot have a vertex form.


What different information do you get from vertex form and quadratic equation in standard form?

The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.


How do you find the vertex of an equation on a graph?

To find the vertex of a quadratic equation in the form (y = ax^2 + bx + c), you can use the formula (x = -\frac{b}{2a}) to determine the x-coordinate of the vertex. Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((x, y)) on the graph. For graphs of other types of functions, the vertex may need to be identified through other methods, such as completing the square or analyzing the graph's shape.


What is the difference between standard form and vertex form?

The difference between standard form and vertex form is the standard form gives the coefficients(a,b,c) of the different powers of x. The vertex form gives the vertex 9hk) of the parabola as part of the equation.


How do you find the vertexof a parabola?

To find the vertex of a parabola given its equation in standard form (y = ax^2 + bx + c), you can use the formula for the x-coordinate of the vertex: (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. Thus, the vertex can be expressed as the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))). For parabolas in vertex form (y = a(x-h)^2 + k), the vertex is simply the point ((h, k)).