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look for the interceptions add these and divide it by 2 (that's the x vertex) for the yvertex you just have to fill in the x(vertex) however you can also use the formula -(b/2a)
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How do you find the equation of a parabola if you know the vertex and a point it passes through?
Use this form: y= a(x-h)² + k ; plug in the x and y coordinates of the vertex into (h,k) and then the other point coordinates into (x,y) and solve for a.
How do you find the x value of the vertex of a quadratic equation?
It depends on the level of your mathematical knowledge. One way is to differentiate the quadratic equation and find the value of x for which the derivative is 0. The advantage of this method is that it works for turning points of polynomials of all degrees. The disadvantage is that you need to know differentiation. For a quadratic, an alternative, and simpler way is to write the equation in the form: y = ax2 + bx + c Then the x value of the vertex is -b/2a
What is the vertex of the equation y equals 2x-1?
3
What the Vertex form of a quadratic equations?
The vertex form of a quatdratic equation (otherwise called the graphing form) is y=a(x-h)2+k For those of you who don't know what 'h', 'a', and 'k' are, they are parameters. The negative sign in front of the 'h' refers to the opposite of the x coordinate in the vertex. The 'k' refers to the y coordinate in the vertex. 'A' refers to the stretch or compression factor. So, for example, say you have a parabola with a stretch factor of 2 whose vertex coordinates are (-3,4). The equation would be y=2(x+3)2+4 Of course, if a parabola has no stretch/compression factor, there would be no 'a' in the equation. I hope this helped, and good luck!
What is the vertex form of a quadratic equation?
The formula for the vertex form is: f(x) = a(x-h)^2 + k Where (h,k) is the vertex. The equation also tells us the direction of opening, which is the a value, in this case opens up because a is positive. It tells us the step pattern, which when a is equal to one is always 1,3,5. However, when the a value is a number other than one, you muct multiply the value by 1,3,5.
What is the equation for vertex form?
The vertex form for a quadratic equation is y=a(x-h)^2+k.
How do you write y equals x minus 4 x plus 2 in vertex form and find the vertex?
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
The vertex form of the equation of a parabola is y x-5 2 plus 16 what is the standard form of the equation?
In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.
What is the vertex form of y -4x2-6x?
The question does not contain an equation: only an expression. An expression cannot have a vertex form.
What different information do you get from vertex form and quadratic equation in standard form?
The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.
What is the difference between standard form and vertex form?
The difference between standard form and vertex form is the standard form gives the coefficients(a,b,c) of the different powers of x. The vertex form gives the vertex 9hk) of the parabola as part of the equation.
How do you find the vertex from a quadratic equation in standard form?
look for the interceptions add these and divide it by 2 (that's the x vertex) for the yvertex you just have to fill in the x(vertex) however you can also use the formula -(b/2a)
What is an equation of the parabola in vertex form that passes through (13 8) and has vertex (3 2).?
please help
What is the formula for quadratic equation in vertex form?
y=2(x-3)+1
Find equation what parabola its vertex is 0 0 and it passes through point 2 12 express the equation in standard form?
Y=3x^2 and this is in standard form. The vertex form of a prabola is y= a(x-h)2+k The vertex is at (0,0) so we have y=a(x)^2 it goes throug (2,12) so 12=a(2^2)=4a and a=3. Now the parabola is y=3x^2. Check this: It has vertex at (0,0) and the point (2,12) is on the parabola since 12=3x2^2
What is the standard form of the equation of the parabola with vertex 00 and directrix y4?
Assuming the vertex is 0,0 and the directrix is y=4 x^2=0
What is an equation of the parabola in vertex form that passes through (13 8)(13 8) and has vertex (3 2)(3 2).?
Vertex form is denoted by: y=a(x-h)2+k Where (h,k) is the vertex. So, we have: y=a(x-2)2+3 (This super\subscript thing is annoying). Plug in the values for x and y for the point in the equation and you have your answer.
