mn = 80
m -n = -79
Substitute
m - 80/m = -79
m^2 - 80 = -79m
m^2 + 79m = 80 (NB Notice change of signs)
Quadratic Eq'n
m = { - 79 +/- sqrt[)79)^2 - 4(1)(-80)}] / 2(1)
m = { - 79 +/- sqrt[6241 + 320}]/ 2
m = { -79 +/- sqrt[6561]} / 2
m = { - 79 +/- 81}/2
m = -160 / 2 = -80 or
m = 2/2 = 1
Hence n = 1 + 79 = 80
80
Oh, dude, you want numbers that add up to 80? Like, I guess you could go with 40 and 40, or 70 and 10, or even 79 and 1 if you're feeling extra spicy. But hey, you do you, man. Math can be wild like that.
x = 79 + 1 is one of the infinite number of such equations.
80
1
80
80 is equal to 80 because it is the same number....... :)ex. (79=79) (100=100)
61, 67, 71, 73, 79, 83, 89, 97, so 79 is nearest
83 is the first prime number after 79.
It is: 79
Oh, dude, you want numbers that add up to 80? Like, I guess you could go with 40 and 40, or 70 and 10, or even 79 and 1 if you're feeling extra spicy. But hey, you do you, man. Math can be wild like that.
80
There are an infinite number of sets with mean 80. Here are some: {80, 80, 80}, {80, 80, 80, 80, 80, 80} {79, 80, 81}, {79, 79, 80, 81, 81}, {79, 79, 80, 82} (1, 80, 159}, {-40, 200} To produce a set of n numbers with mean 80, start with any set of n-1 numbers. Suppose their sum is S. Then add the number 80*n-S to the set. You will now have n numbers whose sum is S+80*n-S = 80*n So the mean of this set is 80.
If three of the four numbers are 79, 80, and 65, and the average is 85, then the final number will equal (85 x 4) - 79 - 80 - 65 = 116.
The number of neutrons is 45 because you subtract 80 to 35.
It is 80 and not 79
It can be rounded to 80, 79 or 79.3