0
mn = 80
m -n = -79
Substitute
m - 80/m = -79
m^2 - 80 = -79m
m^2 + 79m = 80 (NB Notice change of signs)
Quadratic Eq'n
m = { - 79 +/- sqrt[)79)^2 - 4(1)(-80)}] / 2(1)
m = { - 79 +/- sqrt[6241 + 320}]/ 2
m = { -79 +/- sqrt[6561]} / 2
m = { - 79 +/- 81}/2
m = -160 / 2 = -80 or
m = 2/2 = 1
Hence n = 1 + 79 = 80
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What number is after 79?
80
What is 79 rounded to the nearest ten?
80
How many tens are in 79?
1
What is the median of 72 89 67 81 75 79 81 80 62 64 83?
median is 79. Write in order; median is middle number: {72, 89, 67, 81, 75, 79, 81, 80, 62, 64, 83} → {62, 64, 67, 72, 75, 79, 80, 81, 81, 83, 89} To find middle number, count the number of data items, add 1 and divide by 2. If this is a whole number, that is the data item which is the median; if it is a fraction, take the mean average of the data items of the positions either side of the fraction (eg if the fraction is 3.5, take the mean average of the 3rd and 4th data items) There are 11 data items → median is (11+1)/2 = 6th data item → median is 79
What plus 80 makes110?
Subtract the known figure from the known answer to get the missing figure. 110-80=30.
