24 and 21?
58 - 16 = 42, 42/2 = 21, 21 + 16 = 37. Your numbers are 21 & 37
3 & 7? Sum 10, difference 4 so ratio 5:2 or 1 & 21? Sum = 22, difference 20 so ratio 11:10
20 and 1 Seems to be a common problem. Add the sum to the difference and divide by 2 gives one number. Then start over and subtract the smaller of the two givens from the larger and then divide by 2 to get the other number. So here you have (21+19)/2 and (21-19)/2
13 and 8 13 + 8 = 21 13 - 8 = 5
The numbers are 11 and 10
24 and 21?
58 - 16 = 42, 42/2 = 21, 21 + 16 = 37. Your numbers are 21 & 37
3 & 7? Sum 10, difference 4 so ratio 5:2 or 1 & 21? Sum = 22, difference 20 so ratio 11:10
20 and 1 Seems to be a common problem. Add the sum to the difference and divide by 2 gives one number. Then start over and subtract the smaller of the two givens from the larger and then divide by 2 to get the other number. So here you have (21+19)/2 and (21-19)/2
The sum of two numbers witha difference of two equals forty can be set up and solved this way: x + (x - 2) = 40 2x - 2 = 40 2x = 42 x = 21 x - 2 = 19 The two numbers are 21 and 19.
13 and 8 13 + 8 = 21 13 - 8 = 5
8 and 6 have a difference of 2 and a sum of 14.
The two numbers are 10 and 2
Two specific cases of pairs of numbers whose product is 21 are: 1 x 21 and 3 x 7. The ratio of their sum to their difference is: 1 x 21 ... (21+1):(21 - 1) = 22:20 = 11 : 10, and 3 x 7 ... (3+7):(7-3) = 10:4 = 5 : 2. To find a general formula, let the larger number be x and the smaller be 21/x. Their sum is x + 21/x = (x^2 +21)/x Their difference is x - 21/x = (x^2 -21)/x Ratio of sum to difference is [(x^2+21)/x] / [(x^2-21)/x] = [(x^2+21)/x] * [x/(x^2-21)] = (x^2+21)/(x^2-21) Check: This formula produces the results found above.
Three
24,26