Let's denote the two square numbers as x^2 and y^2. The difference between two square numbers can be expressed as (x^2 - y^2), which can be factored into (x + y)(x - y). Since the difference is 80, we have (x + y)(x - y) = 80. The factors of 80 are 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80. By testing out different combinations of these factors, we find that the pair of square numbers that make a difference of 80 is 82^2 and 2^2.
8464 and 3364
They are 25+49 = 74
Multiply the two numbers together and take their square root.
For a pair of numbers, the answer is the complex conjugate pair: 12.5 ± 21.9943 i where i is the imaginary square root of -1.
25 + 49 = 74
They are: 100-16 = 84
16 -9
big cheese
When the order in which they are given makes no difference.
8464 and 3364
The answer to this question can not be answered , many apologies for the inconvenience.
1
17 and 4 have a difference of 13 and is a factor pair of 68
The complex conjugate pair, 4 ± 3.7417i where iis imaginary square root of -1.
There are an infinite number of numbers that have a difference of 16, 16 and 0 is a pair that fits this.
25 and 49.
25 and 49.