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23456 x 10 = 234560..If you are looking for the smallest possible number divisible by 23456, however, that's another ball game. Then you'd have to break both numbers into prime factors:10 = 2 x 523456 = 2 x 2 x 2 x 2 x 2 x 733 (yes, 733 is a prime number)Then you need to make sure that every prime factor from each of these numbers are "represented" in the number that'll be divisible by both 10 and 23456. However prime factors from different numbers can overlap (here the 2 from 10 and one of the 2's from 23456 are not written as two separate factors, but as one).Thus:2 x 5 x 2 x 2 x 2 x 2 x 733 = 10 x 11728 = 117280.Note that as we removed one 2 as a factor, the number is now half of my first and most simple suggestion. This number, however, should be the absolute smallest number divisible by both 10 and 23456.
733.4286
1000
1/3 of 2200 is 733 and 1/3
In order to solve this problem the "blank" should be replace by an x or any other variable. Then 733 should be set equal to x/4. Next is to multiple 4 to both sides to get x to be by itself. After that step is complete the answer would be x = 2932.x/4 = 7334(x/4) = 4(733)x = 2932