23456 x 10 = 234560..
If you are looking for the smallest possible number divisible by 23456, however, that's another ball game. Then you'd have to break both numbers into prime factors:
10 = 2 x 5
23456 = 2 x 2 x 2 x 2 x 2 x 733 (yes, 733 is a Prime number)
Then you need to make sure that every prime factor from each of these numbers are "represented" in the number that'll be divisible by both 10 and 23456. However prime factors from different numbers can overlap (here the 2 from 10 and one of the 2's from 23456 are not written as two separate factors, but as one).
Thus:
2 x 5 x 2 x 2 x 2 x 2 x 733 = 10 x 11728 = 117280.
Note that as we removed one 2 as a factor, the number is now half of my first and most simple suggestion. This number, however, should be the absolute smallest number divisible by both 10 and 23456.
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2 or 8.
No, a number can only be divisible by a number smaller than it
No. 15, 25, 35, and 1675 are divisible by 5, but not by 10. However, every number divisible by 10 is also divisible by 5.
No. Any number that is divisible by 10 is divisible by 5. It doesn't work the other way.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.