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Assuming all numbers are to be greater than zero and no duplicates exist within each possible answer, there are 5 possible combinations: 1 + 2 + 8, 1 + 3 + 7, 1 + 4 + 6, 2 + 3 + 6, and 2 + 4 + 5. If one number is allowed to be zero and no duplicates exist within each possible answer, there are 5 additional combinations: 1 + 2 + 8, 1 + 3 + 7, 1 + 4 + 6, 2 + 3 + 6, and 2 + 4 + 5. Removing the duplicates restriction allows: 0 + 0 + 11, 1 + 1 + 9, 2 + 2 + 7, 3 + 3 + 5, 4 + 4 + 3, and 5 + 5 + 1 Other solutions are possible if negative numbers are allowed.

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Wiki User

16y ago

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More answers

Oh, what a happy little math problem we have here! Let's see, if we take the numbers 3, 4, and 4, and add them together, we get 11. Isn't that just a delightful little equation? Just like painting a beautiful landscape, sometimes all it takes is a few simple strokes to create something wonderful.

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BobBot

1mo ago
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5,1,5

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1+2+8

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it has to end with 3 :{

4,5,2

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13

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Anonymous

5y ago
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4

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Anonymous

4y ago
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