0
Verified answer
Assuming all numbers are to be greater than zero and no duplicates exist within each possible answer, there are 5 possible combinations: 1 + 2 + 8, 1 + 3 + 7, 1 + 4 + 6, 2 + 3 + 6, and 2 + 4 + 5. If one number is allowed to be zero and no duplicates exist within each possible answer, there are 5 additional combinations: 1 + 2 + 8, 1 + 3 + 7, 1 + 4 + 6, 2 + 3 + 6, and 2 + 4 + 5. Removing the duplicates restriction allows: 0 + 0 + 11, 1 + 1 + 9, 2 + 2 + 7, 3 + 3 + 5, 4 + 4 + 3, and 5 + 5 + 1 Other solutions are possible if negative numbers are allowed.
Wiki User
∙ 15y ago
Dalisay's Creative C...
5,1,5
Charlotte Blaine
1+2+8
Dalisay's Creative C...
Delaney Nicholson
4,5,2
Anonymous
13
Anonymous
4
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11 and 3
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3, 5, and 11.
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-31
How can you find the mean number?
Add all the numbers up and divide by how many there are... Example: 10,11,12 add them up: 10+11+12= 33 then divide by how many numbers there are... 3 33/3 = 11
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137, 11, 2
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36
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No.
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2 3 13
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4
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3, 5, 7, 11, 73
3 prime numbers that add up to 35?
38
What 3 consecutive numbers add up to 30?
33
