32
53
1 and 28. 2+27 3+26 4+25 and so on (even after the second numbers turns negative it continues.... forever...)
39
The largest whole number that can go into these three number, 28, 42, and 70 is:142 times 14 equals 283 times 14 equals 425 times 14 equals 70Or it could be 28 if you allowed non-whole numbers in the equation:1 times 28 equals 281.5 times 28 equals 422.5 times 28 equals 70
7*4 equals 28 In multiplication: 4 times 7 = 28 Also, 2 x 14, and 1 x 28
Let the number 'm' & 'n' Hence # Multiplication mn = - 1344 Added m + n = 43 We have two unknowns , So we eliminate one of them . Hence mn = -1344 m = 43 - n Substitute (43 - n) n = -1344 43n - n^(2) = -1344 n^(2) - 43n - 1344 = 0 We now have quadratic eq;n to solve Hence n = { --43 +/- sqrt[(-43)^(2) - 4(1)(-1344)]} / 2(1) n = { 43 +-/ sqrt[ 1849 + 5376]} / 2 n = { 43 +/-sqrt[ 7225] } / 2 n = { 43 +/- 85}/2 n = 128/2 = 64 & n = - 42/2 = -21 Verification 64 X -21 = -1344 64 - 21 = 43 So the two numbers are '-21' & '64'.
5+23=28
-32
32
The numbers are 7 and 28 which equals 35 when added together
28(-28)
28, 35 and 42
21 and 7
-117
Urny ony
28
-14.88153 and 1.88153 (to 5 dp).