Visually it doesn't make sense for an angle to be negative. However we often measure angles off of some axis, such as the x-axis, and positive angles go around counter-clockwise, while negative angles go around clockwise. Outside of the context of a Cartesian Coordinate system (x-y plane), negative angles don't generally make sense.
For certain angles, the answer is yes. For 30o to the horizontal (in the positive x direction), you need to measure the horizontal distance to be twice the vertical distance. For example, draw a triangle with a base length of 10cm and, at a right angle to the base, measure a height of 5cm. The angle to the horizontal (the smaller angle) will be 30o. (The opposite is true for the angle of 60o).
The x axis is the horizontal (flat, bottom, left-right) axis generally, though sometimes they are manipulated to make math easier. -the x axis sometimes represents time The y axis is the vertical (up-down) one.
Positive + Negative = Negative Negative + Negative = Positive Positive + Positive = Positive Negative + Positive = Negative
The complement of any angle is the angle which adds to it to make 90 degrees. In this instance, an angle of 60 degrees adds to 30 to make 90 degrees. Therefore, the complement of 30 degrees is 60 degrees.
Nothing
Apparently so. I answered False and was wrong. I don't really understand how though seeing as magnitude and direction cannot be different, and they are determined by the components, but oh well. The answer is True. * * * * * Translation of the axis will not make a difference to the components but rotation will. Here is a simplified explanation (I hope), with more mathematical details for those who want it. The components of a vector are the projections of the vector along the coordinate axes. If you have a vector, its component along the x-axis is what its "shadow" on the x-axis would be if you shone the light from above - from a direction perpendicular to the x-axis. And its component along the y-axis would be the shadow if you shone a light from a direction perpendicular to the y-axis. Leave the vector as it is and rotate the coordinate axes about the origin and see what happens. The components will change. More advanced: Suppose the original vector, V, had a length of r units and made an angle of A with the x-axis at the origin. then Vx = r*cos(A) and Vy = r*sin(A) Now rotate the axes (anticlockwise) by an angle B. V now makes an angle (A-B) with the new x-axis. then Vx' = r*cos(A-B) and Vy' = r*sin(A-B) These will not be the same unless B = 2*pi*k where k is an integer. That is, only if the axes were rotated through a whole number of circles - back to where it was!
The camber angle is the angle that the wheels of a vehicle make. Specifically, it is the angle between the wheel axis used for steering and the vertical direction of the car.
Visually it doesn't make sense for an angle to be negative. However we often measure angles off of some axis, such as the x-axis, and positive angles go around counter-clockwise, while negative angles go around clockwise. Outside of the context of a Cartesian Coordinate system (x-y plane), negative angles don't generally make sense.
A vector is a quantity with both magnitude (strength) and direction. Like a force having a strength in pounds and a direction. Or a wind having magnitude (in mph) and direction (Northeast). A scalar has only magnitude. Like the length of a segment or amount of peanuts in a jar. Scalars are just numbers.
It isn't, because a mass can only be positive - there are no negative masses. Also mass is only referring to one thing and this doesn't give as much information as a vector quantity. Mass is scalar.
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explain the vector representation of Coulom's law.
They can make an obtuse angle, a straight angle or a reflex angle.
Any plane can make a 90 degree turn on the z axis and keep flying.
Huh?I have been kicking around your question in my mind for five minutes trying to figure out an answer or a way to edit your question into an unambiguous form, but I'm stumped. I don't know what you mean by "zero component along a line."If you look at the representation of a vector on paper using a Cartesian coordinate system -- in other words, one using x and y axes -- the orthogonal components of the vector are the projections of the vector on the x and y axes. If the vector is parallel to one of the axes, its projection on the other axis will be zero. But the vector will still have a non-zero magnitude. Its entire magnitude will project on only one axis.But a vector must have magnitude AND direction. And if it has zero magnitude, its direction cannot be determined.Still trying to make heads or tails out of your question.......If you draw a random vector on a Cartesian grid, it will have an x component and a y component, which are both projections of the original vector upon the axes. However, it could also be represented by projecting it onto a new set of orthogonal axes -- call them x' and y' -- where the x' axis is oriented to be parallel to the original vector and the y' vector is perpendicular to it. In that case, the x' component will have a magnitude equal to the magnitude of the original vector -- in other words, a non-zero value along a line parallel to the x' axis -- and a zero magnitude in the y' direction.
The sine is almost equal to the angle, in case the angle is expressed in radians. Please make a picture of a circle, put a point on the circle at a small angle (say, 10 degrees or less), then draw the sine (a vertical line from the x-axis up to your point) for a small angle. You will see that the arc of the circle has almost the same length as the vertical line you drew. The arc is the angle; the vertical line is the sine.