it would be C because C is the last letter in ac and bc
The definition of a triangle is the union of segments AB, BC, and AC (where A, B, and C are not all collinear).
Assuming that AB and AC are straight lines, the answer depends on the angle between AB and AC. Depending on that, BC can have any value in the range (22, 46).
Draw two lines AB and AC that meet at point A. The angle BAC is greater than 90° but less than 180°. Let AB > AC. Draw a third line BC to complete the triangle so that BC is not equal to AB or AC. The triangle is a scalene triangle containing an obtuse angle.
52.4 cm
it would be C because C is the last letter in ac and bc
All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions
Yes. AB, AC, BC and EF.
Line AB is perpendicular to BC. you can say this like; Line AB is at a right angle to BC
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Consider a right triangle ABC as shown below. The right angle is at B, meaning angle ABC is 90 degrees. With the editor I have, I am not able to draw the line AC but imagine it to be there. By pythagorean theorem AC*2 = AB*2 + BC*2. The line AC is called the hypotenuse. Consider the angle ACB. The cosine of this angle is BC/AC, the sine is AB/AC and tangent is AB/BC. If you consider the angle BAC, then cosine of this angle is AB/AC, the sine is BC/AC and tangent is BC/AB. In general sine of an angle = (opposite side)/(hypotenuse) cosine of an angle = (adjacent side)/(hypotenuse) tangent of an angle = (opposite side)/(adjacent side) |A | | | | | | |______________________C B
Angle B and Angle C
If the sides AB, BC and CA of triangle ABC correspond to the sides DE, EF and FD of triangle DEF, then the two triangles are congruent if:AB = DE, BC = EF and CA = FD (SSS)AB = DE, BC = EF and angle ABC = angle DEF (SAS)AB = DE, angle ABC = angle DEF, angle BCA = angle EFD (ASA)If the triangles are right angled at A and D so that BC and EF are hypotenuses, then the triangles are congruent ifBC = EF and AB = DE (RHS)BC = EF and angle ABC = angle DEF (RHA).
The union of the segments AB, BC, and AC of three nonlinear points A, B, and C.
Draw two line segments, AB and BC, meeting at a right angle at the point B. Pick any point, D, in the plane, which is inside angle ABC or its opposite angle. Join CD and AD. Then ABCD will be a quadrangle which meets the requirements.
If angle ACB is the right angle then ab is the hypotenuse. Then, (ab)2 = 62 + 92 = 36 + 81 = 117 ab = √117 = 10.8 (3 sf) If angle BAC is the right angle then ab is one leg of a right angled triangle with bc the hypotenuse. 92 = 62 + (ab)2 : (ab)2 = 92 - 62 = 81 - 36 = 45 ab = √45 = 6.71 (3 sf)
Angle abc will form a right angle if and only if, segment ab is perpendicular to segment bc.