{ [(1+3) *5 ] +7 } /9 = 3 [4 *5] + 7 = 27 divided by 9 = 3 also [ (1+3) / (5+7) ] * 9 = 3 More complex is 13 * (5+7) - 9 = 3 with just signs : -1 -3 +5 -7 + 9 = 3
The domain of 1 3 5 5 7 7 can not be given because it is not a function.
3+6=9 9-6=3 3+2=5 5+2=7 7-6=1 Heres where it repeats 1+6=7 7-6=1 1+2=3 Answer is 3
9+7+5+3+1 16+5+3+1 21+3+1 24+1 25
3. 1 4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0 2 8 8 4 1 9 7 1 6 9 3 9 9 3 7 5 1 0 5 8 2 0 9 7 4 9 4 4 5 9 2 3 0 7 8 1 6 4 0 6 2 8 6 2 0 8 9 9 8 6 2 8 0 3 4 8 2 5 3 4 2 1 1 7 0 6 7 9 8 2 1 4 8 0 8 6 5 1 3 2 8 2 3 0 6 6 4 7 0 9 3 8 4 4 6 0 9 5 5 0 5 8 2 2 3 1 7 2 5 3 5 9 4 0 8 1 2 8 4 8 1 1 1 7 4 5 0 2 8 4 1 0 2 7 0 1 9 3 8 5 2 1 1 0 5 5 5 9 6 4 4 6 2 2 9 4 8 9 5 4 9 3 0 3 8 1 9 6 4 4 2 8 8 1 0 9 7 5 6 6 5 9 3 3 4 4 6 1 2 8 4 7 5 6 4 8 2 3 3 7 8 6 7 8 3 1 6 5 2 7 1 2 0 1 9 0 9 1 4 5 6 4 8 5 6 6 9 2 3 4 6 0 3 4 8 6 1 0 4 5 4 3 2 6 6 4 8 2 1 3 3 9 3 6 0 7 2 6 0 2 4 9 1 4 1 2 7 3 7 2 4 5 8 7 0 0 6 6 0 6 3 1 5 5 8 8 1 7 4 8 8 1 5 2 0 9 2 0 9 6 2 8 2 9 2 5 4 0 9 1 7 1 5 3 6 4 3 6 7 8 9 2 5 9 0 3 6 0 0 1 1 3 3 0 5 3 0 5 4 8 8 2 0 4 6 6 5 2 1 3 8 4 1 4 6 9 5 1 9 4 1 5 1 1 6 0 9 4 3 3 0 5 7 2 7 0 3 6 5 7 5 9 5 9 1 9 5 3 0 9 2 1 8 6 1 1 7 3 8 1 9 3 2 6 1 1 7 9 3 1 0 5 1 1 8 5 4 8 0 7 4 4 6 2 3 7 9 9 6 2 7 4 9 5 6 7 3 5 1 8 8 5 7 5 2 7 2 4 8 9 1 2 2 7 9 3 8 1 8 3 0 1 1 9 4 9 1 2 9 8 3 3 6 7 3 3 6 2 4 4 0 6 5 6 6 4 3 0 8 6 0 2 1 3 9 4 9 4 6 3 9 5 2 2 4 7 3 7 1 9 0 7 0 2 1 7 9 8 6 0 9 4 3 7 0 2 7 7 0 5 3 9 2 1 7 1 7 6 2 9 3 1 7 6 7 5 2 3 8 4 6 7 4 8 1 8 4 6 7 6 6 9 4 0 5 1 3 2 0 0 0 5 6 8 1 2 7 1 4 5 2 6 3 5 6 0 8 2 7 7 8 5 7 7 1 3 4 2 7 5 7 7 8 9 6 0 9 1 7 3 6 3 7 1 7 8 7 2 1 4 6 8 4 4 0 9 0 1 2 2 4 9 5 3 4 3 0 1 4 6 5 4 9 5 8 5 3 7 1 0 5 0 7 9 2 2 7 9 6 8 9 2 5 8 9 2 3 5 4 2 0 1 9 9 5 6 1 1 2 1 2 9 0 2 1 9 6 0 8 6 4 0 3 4 4 1 8 1 5 9 8 1 3 6 2 9 7 7 4 7 7 1 3 0 9 9 6 0 5 1 8 7 0 7 2 1 1 3 4 9 9 9 9 9 9 8 3 7 2 9 7 8 0 4 9 9 5 1 0 5 9 7 3 1 7 3 2 8 1 6 0 9 6 3 1 8 5 9 5 0 2 4 4 5 9 4 5 5 3 4 6 9 0 8 3 0 2 6 4 2 5 2 2 3 0 8 2 5 3 3 4 4 6 8 5 0 3 5 2 6 1 9 3 1 1 8 8 1 7 1 0 1 0 0 0 3 1 3 7 8 3 8 7 5 2 8 8 6 5 8 7 5 3 3 2 0 8 3 8 1 4 2 0 6 1 7 1 7 7 6 6 9 1 4 7 3 0 3 5 9 8 2 5 3 4 9 0 4 2 8 7 5 5 4 6 8 7 3 1 1 5 9 5 6 2 8 6 3 8 8 2 3 5 3 7 8 7 5 9 3 7 5 1 9 5 7 7 8 1 8 5 7 7 8 0 5 3 2 1 7 1 2 2 6 8 0 6 6 1 3 0 0 1 9 2 7 8 7 6 6 1 1 1 9 5 9 0 9 2 1 6 4 2 0 1 9 8 9
Several solutions. 17 + 1 + 1 + 1 + 1 15 + 3 + 1 + 1 + 1 13 + 5 + 1 + 1 + 1, 13 + 3 + 3 + 1 + 1 11 + 7 + 1 + 1 + 1, 11 + 5 + 3 + 1 + 1, 11 + 3 + 3 + 3 + 1 9 + 9 + 1 + 1 + 1, 9 + 7 + 3 + 1 + 1, 9 + 5 + 5 + 1 + 1, 9 + 5 + 3 + 3 + 1 7 + 7 + 5 + 1 + 1, 7 + 7 + 3 + 3 + 1, 7 + 5 + 5 + 3 + 1, 7 + 5 + 3 + 3 + 3 5 + 5 + 5 + 5 + 1 Note that there is only one solution that does not include 1, namely 7 + 5 + 3 + 3 + 3
{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}{1, 3, 5, 7}
0.6
{ [(1+3) *5 ] +7 } /9 = 3 [4 *5] + 7 = 27 divided by 9 = 3 also [ (1+3) / (5+7) ] * 9 = 3 More complex is 13 * (5+7) - 9 = 3 with just signs : -1 -3 +5 -7 + 9 = 3
3 = 1 x 3 5 = 1 x 5 7 = 1 x 7 GCF = 1
The domain of 1 3 5 5 7 7 can not be given because it is not a function.
(1/3)/(7/15) = 1/(7/5) = 5/7
3+6=9 9-6=3 3+2=5 5+2=7 7-6=1 Heres where it repeats 1+6=7 7-6=1 1+2=3 Answer is 3
9+7+5+3+1 16+5+3+1 21+3+1 24+1 25
Example: 1 + 3/5 = ? Step 1: make the denominators the same: 1 = 5/5 Step 2: put the 5/5 into the problem in place of the 1: 1 + 3/5 = 5/5 +3/5 Step 3: add the numerators: 5/5 + 3/5 = 8/5 Example 2: 3 + 6/7 = ? 3 = (3x7)/7 = 21/7 21/7 + 6/7 = 27/7
Co-prime numbers are those that do not share a greatest common denominator larger than 1. The list of single digit co-primes is below (note that each co-prime also has a conjunctive, where the terms are reversed) (1, 1)(1, 2)(1, 3)(1, 4)(1, 5)(1, 6)(1, 7)(1, 8)(1, 9)(2, 1)(2, 3)(2, 5)(2, 7)(2, 9)(3, 1)(3, 2)(3, 4)(3, 5)(3, 7)(3, 8)(4, 1)(4, 3)(4, 5)(4, 7)(4, 9)(5, 1)(5, 2)(5, 3)(5, 4)(5, 6)(5, 7)(5, 8)(5, 9)(6, 1)(6, 5)(6, 7)(7, 1)(7, 2)(7, 3)(7, 4)(7, 5)(7, 6)(7, 8)(7, 9)(8, 1)(8, 3)(8, 5)(8, 7)(8, 9)(9, 1)(9, 2)(9, 4)(9, 5)(9, 7)(9, 8)
3/5 divided by 1/7 is 21/5 or 4 and 1/5