The numbers are 9, 10 and 11.
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33
87
The integers are even and are 28 and 30.
They are 28, 29 and 30.
Let's represent the three consecutive integers as x, x+1, and x+2. To find their sum, we add these integers together: x + (x+1) + (x+2) = 88. Simplifying the equation gives us 3x + 3 = 88. Subtracting 3 from both sides and then dividing by 3, we find that x = 28. Therefore, the three consecutive integers are 28, 29, and 30, and their sum is indeed 88.