To find 4-digit multiples of 9, we need to start by determining the smallest 4-digit number divisible by 9, which is 1008 (9 x 112). The next multiple would be 1017 (9 x 113), followed by 1026 (9 x 114), and so on, increasing by increments of 9. Therefore, the 4-digit multiples of 9 range from 1008 to 9999.
Oh, let's paint a happy little picture with multiples of 9! If we start with 1000 and add 9 each time, we get 1008, 1017, 1026, and so on. Each of these numbers is a beautiful 4-digit multiple of 9, bringing joy and harmony to our mathematical canvas. Remember, there are countless possibilities in this magical world of numbers!
The common multiples of 4 and 9 are 36, 72, 108 and so on.
There are 5 multiples of 9. There are 4 multiples of 12. There is 1 number that is a multiple of both, 36.
There are 16 4-digit numbers that can be made up from 9 and 6.
To find a common multiple of 3 and 4 that totals 9 less than 50, we first need to list out the multiples of 3 and 4. Multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, and multiples of 4 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48. The common multiples are numbers that appear in both lists. The common multiple that totals 9 less than 50 is 36.
The unit digit of 3127173 is the unit digit of 7173. The other digits of 3127 are multiples of 10 and so they cannot contribute to the unit digit. Now the unit digits of the powers of 7 are Power -- Unit digit 0 -- 1 1 -- 7 2 -- 9 3 -- 3 4 -- 1 and you are back into the loop (of 1-7-9-3). So, you only need consider 7 to the power 173 modulo 4. That is, the remainder when 173 is divided by 4. 173 = 1 mod 4 So the unit digit of 3127173 is the same as the unit digit of 7173 which is the unit digit of 71 which is 7.
Oh, what a happy little question! To find how many 4-digit numbers are multiples of 9, we need to see how many multiples of 9 fall between 1000 and 9999. To do this, we divide the range's endpoints by 9 and subtract the whole numbers in between. By doing this gentle math, we can find the number of delightful 4-digit numbers that are multiples of 9.
-4
There are 720 of them. The three digit counting numbers are 100-999. All multiples of 5 have their last digit as 0 or 5. There are 9 possible numbers {1-9} for the first digit, There are 10 possible numbers {0-9} for each of the first digits, There are 8 possible numbers {1-4, 6-9} for each of the first two digits, Making 9 x 10 x 8 = 720 possible 3 digit counting numbers not multiples of 5.
Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.
Any digit is possible.
The two-digit multiples of nine are 18, 27, 36, 45, 54, 63, 72, 81, 90, 99.
There are 13 two-digit multiples of 7.
There are 9*10*9 = 810 such numbers.
The answer depends on if 4 and 9 WHAT!
3
Any multiple of four must be even; any number ending in three is odd. Look at the multiples of four from 1 to 9. They are in the order : 4,8,12,16,20,24,28,32,36. Now, any number when multiplied by 4, will have the one's digit as the one's digit of the above multiples In the above multiples, no multiple has 3 as the one's digit, i.e., no multiple ends in three. Take an example. 15x4 will have 0 in the one's digit because 5x4 = 20 and has 0 in the one's place.
There are 2000 4-digit numbers that are multiples of 5, so, instead of listing them all, it is equally valid to say: Any4-digit number whose final digit is either a 5 or a 0 is a multiple of 5. Get Right? :P