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To find 4-digit multiples of 9, we need to start by determining the smallest 4-digit number divisible by 9, which is 1008 (9 x 112). The next multiple would be 1017 (9 x 113), followed by 1026 (9 x 114), and so on, increasing by increments of 9. Therefore, the 4-digit multiples of 9 range from 1008 to 9999.
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What are the common multiples of 4 and 9?
The common multiples of 4 and 9 are 36, 72, 108 and so on.
What are the first two common multiples of 4 and 9?
The first two common multiples of 4 and 9 are 36 and 72. To find the common multiples, you need to list the multiples of each number and find where they intersect. The multiples of 4 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, and so on. The multiples of 9 are 9, 18, 27, 36, 45, 54, 63, 72, and so on.
How many 4 digit numbers are possible by 9 and 6?
There are 16 4-digit numbers that can be made up from 9 and 6.
How many multiples of 9 and 12 are there between 1 and 50?
There are 5 multiples of 9. There are 4 multiples of 12. There is 1 number that is a multiple of both, 36.
How do you find the unit digit of 3127 power 173?
The unit digit of 3127173 is the unit digit of 7173. The other digits of 3127 are multiples of 10 and so they cannot contribute to the unit digit. Now the unit digits of the powers of 7 are Power -- Unit digit 0 -- 1 1 -- 7 2 -- 9 3 -- 3 4 -- 1 and you are back into the loop (of 1-7-9-3). So, you only need consider 7 to the power 173 modulo 4. That is, the remainder when 173 is divided by 4. 173 = 1 mod 4 So the unit digit of 3127173 is the same as the unit digit of 7173 which is the unit digit of 71 which is 7.
How many 4 digit numbers that are multiples of 9?
To find the number of 4-digit numbers that are multiples of 9, we first determine the range of 4-digit numbers, which is from 1000 to 9999. Next, we calculate the first and last multiples of 9 within this range, which are 1008 and 9999 respectively. To find the total number of multiples of 9 in this range, we divide the difference between the last and first multiples by 9 and add 1, resulting in (9999 - 1008) / 9 + 1 = 999. Therefore, there are 999 4-digit numbers that are multiples of 9.
How many 5-digit palindromes are multiples of 9?
-4
How many 3 digit counting numbers are not multiples of 5?
There are 720 of them. The three digit counting numbers are 100-999. All multiples of 5 have their last digit as 0 or 5. There are 9 possible numbers {1-9} for the first digit, There are 10 possible numbers {0-9} for each of the first digits, There are 8 possible numbers {1-4, 6-9} for each of the first two digits, Making 9 x 10 x 8 = 720 possible 3 digit counting numbers not multiples of 5.
What numbers are at the end of multiples of 9?
Any digit is possible.
How many 4 digit palindromes are multiples of 9?
Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.
What are the two-digit multiples of 9?
The two-digit multiples of nine are 18, 27, 36, 45, 54, 63, 72, 81, 90, 99.
0 1 2 3 4 5 6 7 8 9 using 2 of these numbers together how many are multiples of 7?
There are 13 two-digit multiples of 7.
How many three digit counting numbers are not multiples of 10?
There are 9*10*9 = 810 such numbers.
What are three multiples if 4 and 9?
The answer depends on if 4 and 9 WHAT!
How many 2 digit whole numbers are multiples of both 6 and 9?
3
Why cant a number that ends on 3 be a multiple of 4?
Any multiple of four must be even; any number ending in three is odd. Look at the multiples of four from 1 to 9. They are in the order : 4,8,12,16,20,24,28,32,36. Now, any number when multiplied by 4, will have the one's digit as the one's digit of the above multiples In the above multiples, no multiple has 3 as the one's digit, i.e., no multiple ends in three. Take an example. 15x4 will have 0 in the one's digit because 5x4 = 20 and has 0 in the one's place.
What are 4 digit numbers that are multiples of 5?
There are 2000 4-digit numbers that are multiples of 5, so, instead of listing them all, it is equally valid to say: Any4-digit number whose final digit is either a 5 or a 0 is a multiple of 5. Get Right? :P
