There are many possible groups of 4 numbers that make 168. 2, 3, 4, 6, 7, 8, 12, 14, 21, 28, 42, 56, and 84 are all factors. Here are a few possibilities for -168. There are others. -- Take the numbers 2, 3, 4, and 7. -- Make any one of them negative, and they multiply to -168. That's 4 solutions. -- Make any 3 of them negative, and they multiply to -168. That's another 4 solutions.
2 x 7 x 12
2*84 3*56 4*42 6*28 7*24 8*21 12*14
-166
48 goes into 168 three times, with a remainder of 24. This can be calculated by dividing 168 by 48, which equals 3 with a remainder of 24. In other words, 48 multiplied by 3 equals 144, and when you subtract 144 from 168, you are left with the remainder of 24.
Exactly 24 times
2 x 7 x 12
These pairs of numbers when multiplied equal 168: (1, 168) (2, 84) (3, 56) (4, 42) (6, 28) (7, 24) (8, 21) (12, 14)
The prime factors of 168 are 23 x 3 x 7.
24 multiplied by 7 is 168.
No. In order for two factors (i.e. two numbers multiplied together) to result in an even number, at least one of the factors must be even. Except for "2" all prime numbers by definition must be odd numbers. 168/2 = 84. 84 is not prime. Therefore you are looking for 2 odd factors of 168. But this is a fruitless search as 2 odd numbers multiplied together will never result in an even number.
2,3 and 28
The numbers below are the factor pairs of 168. Multiplied together they equal 168: (1, 168) (2, 84) (3, 56) (4, 42) (6, 28) (7, 24) (8, 21) (12, 14)
-146
53 + 3 117 - 61 2 x 28 168 / 3 for example.
504/3 = 168 so the three numbers are 167, 168 and 169.504/3 = 168 so the three numbers are 167, 168 and 169.504/3 = 168 so the three numbers are 167, 168 and 169.504/3 = 168 so the three numbers are 167, 168 and 169.
2*84 3*56 4*42 6*28 7*24 8*21 12*14
202