35 to 44
If the last digit were between .1 and .4 you would round down to 35. But if the last digit is .5 or higher (between .5 and .9) you round up to 36. So the answer is 36.
40 and 43, among others.
All the numbers divisible by 5 are the numbers ending with the digit 5 or 0. The first ten examples are: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50
37 rounded to the nearest ten is 40. The 3 is the tens digit and 7 is greater than 5, so it rounds up to 40.
48. Assuming no digit can be used more than once, the two digit numbers divisible by 4 are: 16, 36, 48, 56, 64, 68, 84, 96 8 of them. For any number to be divisible by 4, only the last two digits need be divisible by 4; so for three digit numbers, each of the two digit numbers above can be preceded by any of the remaining 5 digits and still be divisible by 4. → 5 x 8 = 40 three digit numbers are divisible by 4 → 40 + 8 = 48 two or three digit numbers made up of the digits {1, 3, 4, 5, 6, 8, 9} are divisible by 4. If repeats are allowed, there are an extra 2 two digit numbers (44 and 88) and each of the two digit numbers can be preceded by any of the 7 digits, making a total of 7 x 10 + 10 = 80 two and three digits numbers divisible by 4 make up of digits from the given set.
40, if the last digit is 5 or over you round up.
As the digit in the ones place is 3, we round it down, giving 40 as the answer.
The number 1234567890 can create about 39 of 40 4 digit numbers.
40, 51, 62, 73, 84, and 95
40. Excluding numbers starting with 0.
If the last digit were between .1 and .4 you would round down to 35. But if the last digit is .5 or higher (between .5 and .9) you round up to 36. So the answer is 36.
30 and 40
40 and 43, among others.
The number is 42.
9000 500 40 and 3
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
42