The sum of all the odd numbers from 1 through 100 is 10,000
The sum of the first 100 odd numbers (1 through 199) is 10000 (ten thou)
Thereare 50 odd numbers and 50 even numbers in that range, so the probability is 1 out of 2
201
100
The sum of all the odd numbers from 1 through 100 is 10,000
They are: 13579111315171921232527293133353739414345474951535557596163656769717375777981838587899193959799.
Look for a table of prime numbers. All the odd numbers that are NOT on this list are composite numbers.
101
over 50
The sum of the even numbers is (26 + 28 + ... + 100); The sum of the odd numbers is (25 + 27 + ... + 99) Their difference is: (26 + 28 + ... + 100) - (25 + 27 + ... + 99) = (26 - 25) + (28 - 27) + ... + (100 - 99) = 1 + 1 + ... + 1 There are (100 - 26) ÷ 2 + 1 = 38 terms above which are all 1; their sum is 38 x 1 = 38. So the difference of the sum of all even numbers and all odd numbers 25-100 is 38.
The sum is 2500.
101
Since odd numbers are in a ratio of 1:2 it means for every one odd there will be one even, there would be 50 odd numbers between 1-100, and 50 even numbers. So 50%.
All numbers ending with 1,3,5,7 and 9 including those numbers as well. 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,37,39,41,43,45,47,49,51,53,55,57,59,61,63,65,67,69,71,73,75,77,79,81,83,85,87,89,91,93,95,97,99.
All numbers ending with 1,3,5,7 and 9 including those numbers as well. 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,37,39,41,43,45,47,49,51,53,55,57,59,61,63,65,67,69,71,73,75,77,79,81,83,85,87,89,91,93,95,97,99.
In Java:System.out.println("Even numbers")for (int i = 2; i